2. Find the solution of the given initial value problem using MUC: 2y(3) – y(2) – 2y(1) + y = 4x3 – 2xe-3x + 5 sin 4x y(0) = 1, y'(0) = -2, y"(0) = 3 Find its particular solution. b. yp = -4x3 – 24x2 – 120x – 240 – e-3x a. yp = 4x3 + 24x² + 120x + 240 + 29 -3x + sin(4x) – 8 29 8 cos(4x) – -3x -3x + e 784 28 1 221 28 221 784 221 sin(4x) 4x3 + 24x2 + 120x + 240 + d. Yp -cos(4x) 221 С. Ур 4x3 + 24x2 + 120x + 240 + 29 e-3x 784 29 -e-3x + e 784 X-3x -sin(4x) + -3x + cos(4x) + 28 8 sin(4x) 221 28 8. -cos(4x)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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2. Find the solution of the given initial value problem using MUC:
2y(3) – y(2) – 2y(1) + y = 4x3 – 2xe-3x + 5 sin 4x y(0) = 1, y'(0) = -2, y"(0) = 3
Find its particular solution.
b. yp = -4x3 – 24x2 – 120x – 240 –
e-3x
a. yp = 4x3 + 24x² + 120x + 240 +
29
-3x
+ sin(4x) –
8
29
8
cos(4x) –
-3x
-3x
+
e
784
221
28
1
221
784
28
1
-cos(4x)
221
221 sin(4x)
С. Ур
4x3 + 24x2 + 120x + 240 +
d. Ур
4x3 + 24x2 + 120x + 240 +
29
29
e-3x
784
-3x +
e
784
-sin(4x) +
e-3x
28
8.
cos(4x)
221
-3x
cos(4x) +
28
8.
221
221
Transcribed Image Text:2. Find the solution of the given initial value problem using MUC: 2y(3) – y(2) – 2y(1) + y = 4x3 – 2xe-3x + 5 sin 4x y(0) = 1, y'(0) = -2, y"(0) = 3 Find its particular solution. b. yp = -4x3 – 24x2 – 120x – 240 – e-3x a. yp = 4x3 + 24x² + 120x + 240 + 29 -3x + sin(4x) – 8 29 8 cos(4x) – -3x -3x + e 784 221 28 1 221 784 28 1 -cos(4x) 221 221 sin(4x) С. Ур 4x3 + 24x2 + 120x + 240 + d. Ур 4x3 + 24x2 + 120x + 240 + 29 29 e-3x 784 -3x + e 784 -sin(4x) + e-3x 28 8. cos(4x) 221 -3x cos(4x) + 28 8. 221 221
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