2. Find the inverse of a matrix if it exists and use it to solve this system of linear equations. Be sure to show and explain your work. -2y + 5x = -44 x + 5y = 2

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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**Problem 2: Find the inverse of a matrix if it exists and use it to solve the system of linear equations. Be sure to show and explain your work.**

Given system of linear equations:
\[
-2y + 5x = -44
\]
\[
x + 5y = 2
\]

### Solution:

1. **Form the system in matrix form \(AX = B\):**

   The system of equations can be written in matrix form \(AX = B\), where:
   \[
   A = \begin{pmatrix}
          5 & -2 \\
          1 & 5 \\
       \end{pmatrix}, \quad
   X = \begin{pmatrix}
          x \\
          y \\
       \end{pmatrix}, \quad
   B = \begin{pmatrix}
          -44 \\
          2 \\
       \end{pmatrix}
   \]

2. **Find the inverse of matrix \(A\):**

   The inverse \(A^{-1}\) of a \(2 \times 2\) matrix \(A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}\) is given by:
   \[
   A^{-1} = \frac{1}{ad - bc}
            \begin{pmatrix}
               d & -b \\
              -c & a \\
            \end{pmatrix}
   \]
   For the matrix \(A = \begin{pmatrix}
                         5 & -2 \\
                         1 & 5 \\
                        \end{pmatrix}\):
   \[
   ad - bc = (5 \cdot 5) - (-2 \cdot 1) = 25 + 2 = 27
   \]
   So, the inverse is:
   \[
   A^{-1} = \frac{1}{27}
            \begin{pmatrix}
               5 & 2 \\
              -1 & 5 \\
            \end{pmatrix}
           = \begin{pmatrix}
               \frac{5}{27} & \frac{2}{27} \\
              -\frac{1}{27} & \frac{5}{27} \\
            \end{pmatrix}
   \]

3. **Solve for \(X
Transcribed Image Text:**Problem 2: Find the inverse of a matrix if it exists and use it to solve the system of linear equations. Be sure to show and explain your work.** Given system of linear equations: \[ -2y + 5x = -44 \] \[ x + 5y = 2 \] ### Solution: 1. **Form the system in matrix form \(AX = B\):** The system of equations can be written in matrix form \(AX = B\), where: \[ A = \begin{pmatrix} 5 & -2 \\ 1 & 5 \\ \end{pmatrix}, \quad X = \begin{pmatrix} x \\ y \\ \end{pmatrix}, \quad B = \begin{pmatrix} -44 \\ 2 \\ \end{pmatrix} \] 2. **Find the inverse of matrix \(A\):** The inverse \(A^{-1}\) of a \(2 \times 2\) matrix \(A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}\) is given by: \[ A^{-1} = \frac{1}{ad - bc} \begin{pmatrix} d & -b \\ -c & a \\ \end{pmatrix} \] For the matrix \(A = \begin{pmatrix} 5 & -2 \\ 1 & 5 \\ \end{pmatrix}\): \[ ad - bc = (5 \cdot 5) - (-2 \cdot 1) = 25 + 2 = 27 \] So, the inverse is: \[ A^{-1} = \frac{1}{27} \begin{pmatrix} 5 & 2 \\ -1 & 5 \\ \end{pmatrix} = \begin{pmatrix} \frac{5}{27} & \frac{2}{27} \\ -\frac{1}{27} & \frac{5}{27} \\ \end{pmatrix} \] 3. **Solve for \(X
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