2. Find the area of a parallelogram defined by PQ and QR when P = (4, 0, 1), Q = (5, -3, 0), and R = (-2, -5, -3). A= || ŷ xWll På= (5-4, (-3-0), (0-1)) = (キ+3) (7, 10,-295 %3D %3D <9-2) (-2 -27)7 49+100 +841 =N 990 %3D

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2. Find the area of a parallelogram defined by PQ and QR when P = (4, 0, 1),
Q = (5, -3, 0), and R = (-2, -5, -3).
A-|ixil ré: (5-4)(-ち-0), 10-1) - <
A=| Få XORI åR = (-2-5, (-5-(-3), (-3-0)= <-2, -2,-37
伝x aR = <-3-う)- (-2),(-ル-7)-(い-3),(11-2)-(-3-)>
(キ+3)
く3, 0-29)
wz W3
くA-2)
(-2 -27)7
ll På x QRII= Ja?+10?+(-29)? = 49 + 100 +841
990
Transcribed Image Text:2. Find the area of a parallelogram defined by PQ and QR when P = (4, 0, 1), Q = (5, -3, 0), and R = (-2, -5, -3). A-|ixil ré: (5-4)(-ち-0), 10-1) - < A=| Få XORI åR = (-2-5, (-5-(-3), (-3-0)= <-2, -2,-37 伝x aR = <-3-う)- (-2),(-ル-7)-(い-3),(11-2)-(-3-)> (キ+3) く3, 0-29) wz W3 くA-2) (-2 -27)7 ll På x QRII= Ja?+10?+(-29)? = 49 + 100 +841 990
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