### Physics Problem: Finding Mass for Constant Speed Motion**Problem Statement:**2. **Find \( M \) so blocks move at a constant speed.****Diagram Explanation:**The diagram shows a 2 kg block on a horizontal surface connected by a pulley to a hanging block of mass \( M \). The coefficient of friction (\( \mu \)) between the 2 kg block and the surface is 0.2.**Forces on the 2 kg Block (on the horizontal surface):**- **Weight (\( m \cdot g \))**: Vertically downward force, where \( m = 2 \) kg and \( g = 9.8 \, \text{m/s}^2 \).- **Normal Force (\( F_n \))**: Vertically upward force equal in magnitude to the weight of the block.- **Frictional Force (\( F_f \))**: Horizontally opposing the direction of motion, calculated as \( F_f = \mu \cdot F_n \).- **Tension (\( T \))**: Horizontally towards the pulley.**Forces on the Hanging Block (\( M \)):**- **Weight (\( Mg \))**: Vertically downward force due to gravity.- **Tension (\( T \))**: Vertically upward force opposite to the weight.**Condition for Constant Speed:**For the system to move at a constant speed, the net force acting on both blocks must be zero, which means:- The tension in the string must balance the frictional force on the 2 kg block.- The weight of the hanging block must balance the tension in the string.**Equation for Constant Speed:**- Using the equation \(\sum F = ma = 0\), solve for the mass \( M \) such that these conditions are satisfied.**Conclusion:**The problem requires solving for the mass \( M \), ensuring the system maintains a constant speed by balancing all forces involved. An understanding of forces, friction, and tension in a mechanical system is necessary to find the correct mass \( M \).

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Description: ### Physics Problem: Finding Mass for Constant Speed Motion**Problem Statement:**2. **Find \( M \) so blocks move at a constant speed.****Diagram Explanation:**The diagram shows a 2 kg block on a horizontal surface connected by a pulley to a hanging

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2. Find M so blocks move at a constant speed. Fn 2 kg μ=0.2 M ≤F=

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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### Physics Problem: Finding Mass for Constant Speed Motion

**Problem Statement:**

2. **Find \( M \) so blocks move at a constant speed.**

**Diagram Explanation:**

The diagram shows a 2 kg block on a horizontal surface connected by a pulley to a hanging block of mass \( M \). The coefficient of friction (\( \mu \)) between the 2 kg block and the surface is 0.2.

**Forces on the 2 kg Block (on the horizontal surface):**

- **Weight (\( m \cdot g \))**: Vertically downward force, where \( m = 2 \) kg and \( g = 9.8 \, \text{m/s}^2 \).
- **Normal Force (\( F_n \))**: Vertically upward force equal in magnitude to the weight of the block.
- **Frictional Force (\( F_f \))**: Horizontally opposing the direction of motion, calculated as \( F_f = \mu \cdot F_n \).
- **Tension (\( T \))**: Horizontally towards the pulley.

**Forces on the Hanging Block (\( M \)):**

- **Weight (\( Mg \))**: Vertically downward force due to gravity.
- **Tension (\( T \))**: Vertically upward force opposite to the weight.

**Condition for Constant Speed:**

For the system to move at a constant speed, the net force acting on both blocks must be zero, which means:

- The tension in the string must balance the frictional force on the 2 kg block.
- The weight of the hanging block must balance the tension in the string.

**Equation for Constant Speed:**

- Using the equation \(\sum F = ma = 0\), solve for the mass \( M \) such that these conditions are satisfied.

**Conclusion:**

The problem requires solving for the mass \( M \), ensuring the system maintains a constant speed by balancing all forces involved. An understanding of forces, friction, and tension in a mechanical system is necessary to find the correct mass \( M \).

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