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2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons in the product and the # in the starting material tells us the # in the carbonyl. The fact that we form only one product tells us the identity of the carbonyl.) C8H9Br 1H NMR: 7.3-7.1 (m, 5H) 3.5 (t, 2H) 3.1 (t, 2H) 1) Ph3P 2) nBuLi phosphonium ylide carbonyl C1114 (only one product formed)

2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons in the product and the # in the starting material tells us the # in the carbonyl. The fact that we form only one product tells us the identity of the carbonyl.) C8H9Br 1H NMR: 7.3-7.1 (m, 5H) 3.5 (t, 2H) 3.1 (t, 2H) 1) Ph3P 2) nBuLi phosphonium ylide carbonyl C1114 (only one product formed)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons in the product and the # in the starting material tells us the # in the carbonyl. The fact that we form only one product tells us the identity of the carbonyl.) C8H9Br 1H NMR: 7.3-7.1 (m, 5H) 3.5 (t, 2H) 3.1 (t, 2H) 1) Ph3P 2) nBuLi phosphonium ylide carbonyl C1114 (only one product formed)
Transcribed Image Text:2. Fill in the boxes in the following problem. (Hints: The difference between the # of carbons in the product and the # in the starting material tells us the # in the carbonyl. The fact that we form only one product tells us the identity of the carbonyl.) C8H9Br 1H NMR: 7.3-7.1 (m, 5H) 3.5 (t, 2H) 3.1 (t, 2H) 1) Ph3P 2) nBuLi phosphonium ylide carbonyl C1114 (only one product formed)
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