2. Dr. Dahm has a 0.4 M solution of nitrous acid. If he takes 3 mL of this solution and dilutes it to 100 mL calculate the pH of the new solution. (assume that no dissociation takes place until the new solution is made.) Ka = 4.6´ 10-4 HNO₂(aq) + H₂O(1) NO₂ (aq) H,O*(aq) +
2. Dr. Dahm has a 0.4 M solution of nitrous acid. If he takes 3 mL of this solution and dilutes it to 100 mL calculate the pH of the new solution. (assume that no dissociation takes place until the new solution is made.) Ka = 4.6´ 10-4 HNO₂(aq) + H₂O(1) NO₂ (aq) H,O*(aq) +
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter17: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 110CWP
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Question
![### Problem Statement
Dr. Dahm has a 0.4 M solution of nitrous acid. If he takes 3 mL of this solution and dilutes it to 100 mL, calculate the pH of the new solution. Assume that no dissociation takes place until the new solution is made. The dissociation constant, \( K_a \), for nitrous acid is \( 4.6 \times 10^{-4} \).
### Chemical Reaction
\[ \text{HNO}_2(aq) + \text{H}_2\text{O}(l) \rightarrow \text{H}_3\text{O}^+(aq) + \text{NO}_2^-(aq) \]
### Explanation
1. **Dilution Calculation:**
- Initial concentration (\( C_i \)) = 0.4 M
- Initial volume (\( V_i \)) = 3 mL
- Final volume (\( V_f \)) = 100 mL
Use the dilution formula:
\[
C_f = \frac{C_i \times V_i}{V_f}
\]
Calculate the new concentration (\( C_f \)) after dilution.
2. **pH Calculation:**
- Use the dissociation constant (\( K_a \)) to find the concentration of \( \text{H}_3\text{O}^+ \).
- Calculate the pH using:
\[
\text{pH} = -\log [\text{H}_3\text{O}^+]
\]
The task involves using chemical equilibrium concepts to find the pH of the solution after dilution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ef19cdf-d917-4e85-90d1-e182276b5042%2F89a38fb4-230b-49c5-acbf-645b7b54aacd%2Fqe3zzdd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Statement
Dr. Dahm has a 0.4 M solution of nitrous acid. If he takes 3 mL of this solution and dilutes it to 100 mL, calculate the pH of the new solution. Assume that no dissociation takes place until the new solution is made. The dissociation constant, \( K_a \), for nitrous acid is \( 4.6 \times 10^{-4} \).
### Chemical Reaction
\[ \text{HNO}_2(aq) + \text{H}_2\text{O}(l) \rightarrow \text{H}_3\text{O}^+(aq) + \text{NO}_2^-(aq) \]
### Explanation
1. **Dilution Calculation:**
- Initial concentration (\( C_i \)) = 0.4 M
- Initial volume (\( V_i \)) = 3 mL
- Final volume (\( V_f \)) = 100 mL
Use the dilution formula:
\[
C_f = \frac{C_i \times V_i}{V_f}
\]
Calculate the new concentration (\( C_f \)) after dilution.
2. **pH Calculation:**
- Use the dissociation constant (\( K_a \)) to find the concentration of \( \text{H}_3\text{O}^+ \).
- Calculate the pH using:
\[
\text{pH} = -\log [\text{H}_3\text{O}^+]
\]
The task involves using chemical equilibrium concepts to find the pH of the solution after dilution.
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