2. Do the boundary condition problem below by filling the missing values (?) and state which of the six rules you used in each case. Boundary condition problem No free surface charge or current Given Ē, B, find all the ?s E1 = 2ɛ0, Hi = Ho, 01 = 0 E2 = 4ɛ0, H2 = 2µo, 02 = 0 Bi/Ho = 6£ + 7ŷ + 82 B. =?&+? ŷ+? 2 Ho E, = 2â + 4ỹ + 62 E2 =? &+? ŷ+? 2 D/ɛ0 =? &+? ŷ+? 2 H =?&+? ŷ+? 2 Dz/E0 =?&+? ŷ+? 2 H2 =?&+?§+? 2 Apply Boundary conditions =; 1. D = eE 2. B = µH 3. îz x (E, – Ë,) = 0 4. îz x (H, – H,) =Js 5. fîz (B, – B.) = 0 6. îz · (D, – D2) = 05
2. Do the boundary condition problem below by filling the missing values (?) and state which of the six rules you used in each case. Boundary condition problem No free surface charge or current Given Ē, B, find all the ?s E1 = 2ɛ0, Hi = Ho, 01 = 0 E2 = 4ɛ0, H2 = 2µo, 02 = 0 Bi/Ho = 6£ + 7ŷ + 82 B. =?&+? ŷ+? 2 Ho E, = 2â + 4ỹ + 62 E2 =? &+? ŷ+? 2 D/ɛ0 =? &+? ŷ+? 2 H =?&+? ŷ+? 2 Dz/E0 =?&+? ŷ+? 2 H2 =?&+?§+? 2 Apply Boundary conditions =; 1. D = eE 2. B = µH 3. îz x (E, – Ë,) = 0 4. îz x (H, – H,) =Js 5. fîz (B, – B.) = 0 6. îz · (D, – D2) = 05
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
Transcribed Image Text:2. Do the boundary condition problem below by filling the missing values (?) and state which of the six rules
you used in each case.
Boundary condition problem
No free surface charge or current
Given Ej, B, find all the ?s
E = 2€0,
4ɛ0, µz = 2µ0,
02 = 0
%3D
H1 = Ho,
01 = 0
y
E = 28 + 4ỹ + 62
B1/Ho = 6£ + 7ŷ + 82
B2
%3D
E2 =? &+? ŷ+? 2
- =? &+? ŷ+? 2
Ho
Di /Eo =? &+? ŷ+? Ż
H =?&+? ŷ+?2
D2/E0 =?&+? ŷ+? 2 H2 =?&+?ŷ+? 2
Apply Boundary conditions =:
1. D = EE
2. B = µ H
3. îz x (Ë, – Ë2) = 0
4. îz × (H1 – Ħ2) = J,
5. fîz · (B1 – B2) = 0
6. îz · (D, – D2) = 0s
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