2. Determine the location of the center of gravityof a wire with uniform cross- sectional area andspecific weight., shown in the figure below. Thewire is in the form of a broken line P, P2 P3 P4,with P:(-3, 7), P2(-1, 1), P3 (3, 5) and P. (5, 3).C.G. (0.30, 3.60)Pi-3, 7)P(3, 5)M(-2, 4)8 M5(1, 3) XM(4, 4)PA(5, 3)P2(-1, 1)

First we will determine the center of gravity for each wire segment, which will be the mid-point for…

Answered: 2. Determine the location of the center…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question Find the resultant force and couple moment at A. TBC = 792 N TBD = 208 N 2 m 6 m 3 m 800 N 3 m 350 N 4 m
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To solve for the moment and reactions of the beam shown, the three-moment equation is useful. The three moment equation is given as: 6Ab 6Aa + L1 MĄ(L1) + 2Mg(L1+ L2 + MCL2) + Assuming that there is no settlement of supports and El is constant for the whole structure. 6Aa 6Ab is called the "Factors" of the three-moment equation which can be determined by using the Moment-Area diagram of the left span and right span of the beam and also by L1 using integral calculus. L2 For the loading shown below, determine the value of the resulting "Factors" when W1 = W2 = 17 kN/m, a = 3 meters, b = 2 meters. ROUND OFF TO TWO DECIMAL PLACES. W1 W2 A a a b b b
6
SITUATION. The tower for a transmission line is modeled by the truss shown. The crossed members in the center section of the truss may be assumed to be capable of supporting tension only. Given: P=2.8kN 0=15⁰ a=3m b=3m c = 5m 5 panels@(a)m each F E b B b b P G C Zoom image Compute the force induced in member AB
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Question Find the resultant force and couple moment at A. TBC = 792 N TBD = : 208 N 2m 6 m 3 m B 800 N 3 m D 4 m 350 N ∙y

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2. Determine the location of the center of gravity of a wire with uniform cross- sectional area and specific weight., shown in the figure below. The wire is in the form of a broken line P, P2 P3 P4, with P:(-3, 7), P2(-1, 1), P3 (3, 5) and P4 (5, 3).