2. Determine if the limits of the following function exists. If it exist, 2х2 - ху — у? give the value of the limit. lim (х,у)-(1,1) Зx2 — 17х — 28 trial paths: X = 1 and y is any number y = 1 and x is any number X = y x = y? X

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A: Dear student as per our rule in one session we can only solve one question. Please post the other…

Q: Find the limit. 2 – 4x². - 9x + 11 lim - 8x + 6x +2 X00 11 OA. 2 ОВ. оо OC. O D. 1 F/N 8

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Q: Find the limits by rewriting the fractions first.

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Q: 8x2 — 5х + 1 2) lim *о 4x2 — 2х +4 —Зх + 2 3) lim *о 4x2 + х + 4 4x2 — Зх + 2 4) lim х+4

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Q: a. lim (3x - 5) x->-1 b.lim x² -9 xxxx²²-4x+3 2 x²-9 c.lim XX x² - 4x +3 2

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Q: 3. (4 points) Find the limit (if it exists): 2xh – 5h + 3h? lim h

A: limit value=?

Q: Evaluate the following limit: 2(х-1)у lim (x.y) → (1,0) (x- 1)3+y® Select one: None of the others.…

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A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: 4x2+11х-3 (i) lim x→-3 9—х2 (ii) lim 2 -1 *-4 х36 6-х Vx2+9-V2x2+9 (iii) lim х-0 VЗx2+4-V2х2+4

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Q: evaluate the limit.

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Q: Q2: Find the limit of the following function; бе4x — е-2х lim x-00 8e4x – e2x +3e-x

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