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2. Data for liquid mercury at 298 K and 100 kPa: V= 14.72 cm/mol B = 181 x 106 K KT = 38.9x 1012 pa". Calculate the pressure increase above 100 kPa required to cause 0.1% decrease in V.

2. Data for liquid mercury at 298 K and 100 kPa: V= 14.72 cm/mol B = 181 x 106 K KT = 38.9x 1012 pa". Calculate the pressure increase above 100 kPa required to cause 0.1% decrease in V.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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2. Data for liquid mercury at 298 K and 100 kPa: V= 14.72 cm/mol -1 B = 181 × 106 K 38.9x 1012 pa'. Calculate the KT pressure increase above 100 kPa required to cause 0.1% decrease in V.
Transcribed Image Text:2. Data for liquid mercury at 298 K and 100 kPa: V= 14.72 cm/mol -1 B = 181 × 106 K 38.9x 1012 pa'. Calculate the KT pressure increase above 100 kPa required to cause 0.1% decrease in V.
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