2. Consider the points P = (3, 2, –1), Q = (-1,1, 1), and R = (-3,0, 2). %3D (a) Find parametric and cartesian equations for the plane P1 that goes through the three points. (b) Find cartesian equations for the plane P2 that goes through the point P and is perpendicular to both P1 and to the plane with equation a- means that a normal vector to P2 needs to be orthogonal to both a normal vector of P1 and to a normal vector of the plane with equation x - 4y + 2z = 4. (Hint: the perpendicularity condition 4y + 2z = 4. And you do know how to find a vector that is orthogonal to two other vectors.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 36E
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Consider the points P = (3, 2, –1), Q = (-1,1, 1), and R = (-3,0, 2).
(a) Find parametric and cartesian equations for the plane Pi that goes through the three points.
(b) Find cartesian equations for the plane P2 that goes through the point P and is perpendicular to
both P1 and to the plane with equation x – 4y + 2z = 4. (Hint: the perpendicularity condition
means that a normal vector to P2 needs to be orthogonal to both a normal vector of P1 and to a
normal vector of the plane with equation x – 4y + 2z = 4. And you do know how to find a vector
that is orthogonal to two other vectors.)
-
-
2.
Transcribed Image Text:Consider the points P = (3, 2, –1), Q = (-1,1, 1), and R = (-3,0, 2). (a) Find parametric and cartesian equations for the plane Pi that goes through the three points. (b) Find cartesian equations for the plane P2 that goes through the point P and is perpendicular to both P1 and to the plane with equation x – 4y + 2z = 4. (Hint: the perpendicularity condition means that a normal vector to P2 needs to be orthogonal to both a normal vector of P1 and to a normal vector of the plane with equation x – 4y + 2z = 4. And you do know how to find a vector that is orthogonal to two other vectors.) - - 2.
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