2. Compute the x and y coordinates from the following balanced data.BalancedLength (ft.) Latitude Departure Latitude Departure PointsASideBearingdegree minutesAB S 6BC S 29CD N 81DE N 1215 W 189.53 -188.403 -20.634 -188.388 -20.60138 E 175.18 -152.268 86.617 -152.253 86.64818 W 197.78 29.916 -195.504 29.933 -195.47024 W 142.39 139.068 -30.576 139.080 -30.551EAN 42 59 E 234.58 171.607 159.933 171.627939.46 -0.079 -0.163 0.000159.9740.000ABCDEAсDACoordinatesy100.000 100.000X3. Compute the area of the given data in problem no. 2 using the TWO introducedCoordinate Method.

Side Bal. Latitude Bal. Departure Point Co-ord X Co-ord Y AB -188.388…

2. Compute the x and y coordinates from the following balanced data. Side Bearing degree minutes AB S 6 BC S 29 CD N 81 DE N 12 EAN 42 Balanced Length (ft.) Latitude Departure Latitude Departure Points 15 W 189.53 -188.403 -20.634 -188.388 -20.601 38 E 175.18 -152.268 86.617 -152.253 86.648 18 W 24 W 59 E 197.78 29.916 -195.504 142.39 139.068 -30.576 234.58 171.607 159.933 939.46 -0.079 -0.163 29.933 -195.470 139.080 -30.551 171.627 159.974 0.000 0.000 ABCDEA Coordinates y 100.000 100.000 x 3. Compute the area of the given data in problem no. 2 using the TWO introduced Coordinate Method.

2. Compute the x and y coordinates from the following balanced data. Side Bearing degree minutes AB S 6 BC S 29 CD N 81 DE N 12 EAN 42 Balanced Length (ft.) Latitude Departure Latitude Departure Points 15 W 189.53 -188.403 -20.634 -188.388 -20.601 38 E 175.18 -152.268 86.617 -152.253 86.648 18 W 24 W 59 E 197.78 29.916 -195.504 142.39 139.068 -30.576 234.58 171.607 159.933 939.46 -0.079 -0.163 29.933 -195.470 139.080 -30.551 171.627 159.974 0.000 0.000 ABCDEA Coordinates y 100.000 100.000 x 3. Compute the area of the given data in problem no. 2 using the TWO introduced Coordinate Method.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Calculate the closing error of the following traverse Line Length (m) AB 193.20 BC 176.80 CD 375.50 DE EA O 0.90 O 0.71 O 0.81 O 0.79 O 0.83 410.90 158.50 Direction S 06° E S 40° W N 81° W N 48° E S 88° E
Compute for the coordinates of station O. Note that: A has a northing of 1620925.334 and easting of 507672.847. B has a northing of 1620923.996 and easting of 507617.614. C has a northing of 1620694.527 and easting of 507681.770. STATION OCCUPIED STATION OBSERVED HORIZONTAL ANGLE (m) O B 0˚00’00” A 0˚29’49” O A 0˚00’00” C 64˚08’18”
On the drawing below, Datum feature B is perpendicular to what? D 10 Ø3.000 .020 O Nothing Datum feature D O Datum feature B Datum feature C D O Datum feature A 45° 4X Ø.395-.430 Ø.500-.510 0.020M ABMCM +0.010M ADM -.375-.395 +.000MABM Ø2.000 C A 0.005MA B
Azimuth Azimuth Fraction) Length Degrees Minutes Seconds Line 10047 86.99 100 28 AB 44 186.18 186 10 BC 259 89 0.00 CD 100.11 125.32 115 12 44 115.21 DE 323 10 323.17 EA 284.548 SUM 856.858 7. Determine the FGCC dassification of the angle measurements in the problem shown here. Interior Angles Degrees Minutes Seconds 80 28 86 10 44 100 01 215 12 4. 58 3. 18 SUM 69
AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S AB 7i5.20 1200.53 вс CD DE 401.78 414.29 1735.58 419.88 1606.43 456.66 200.70 EF 617.59 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N -S +E - w 281.06 1-2 2-3 281.28 168.75 449.32 337.56 281.22 T12,50 450.66 450.03 225.08 450.06 335.86 Sums +900.09 m 900.09 m+1011.60mHio11.6Om N3456- -2345
3. Given the following three wire leveling notes: Station Backsight Stadia BM1 Foresight Stadia Elevation 425.00 1.152 1.117 0.935 0.899 0.718 0.662 TP1 2.784 1.904 2.420 1.537 2.057 1.172 ТР2 2.591 2.210 2.094 1.714 1.599 1.218 BM2 a. Find the difference in elevation of TP2 and BM1, b. Find the elevation of BM2
What is the direction of the closing error for the following data? Line AB BC CA Length (m) 24.29 130.32 d. 249.11 a. 60°23¹ b. 60°29¹ c. 50⁰23¹ 62023¹ Latitude -102.31 +360.24 -257.43 Departure -119.22 -204.92 +323.26
Compute the Area using the DMD and check by DPD method ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N +E W AB 552.45 212.63 BC 232.06 396.50 CD 359.70 283.15 DE 209.37 366.89 EA 215.44 525.39 Sume 784.51m-784.5 1m+892.28m-892.28m (NL) (SL) (ED) (WD)
A closed traversed has the following data. LINE DISTANCE BEARING AB 185.33 N 43 E BC 258.28 S 67 E CD ? S 38 W DE ? S 81 W EA 150.87 N 27 W The summation of the latitude and departure of the traverse are -26 and 55, respectively. Using COMPASS RULE, determine the follwowing:(Round off into four decimal places)DETERMINE THE CORRECTED LATITUDE OF THE LINE CD.
2. Complete the missing data. LINE DISTANCE (feet) BEARING AB 74.6039 DUE SOUTH ВС 132.2039 S 61.870 E CD 167.9143 N 75.55° E DE 183.9141 N 19.15° E EF 183.2644 N 59.88° W FG 124.8922 N 21.12° E GH 296.5704 DUE WEST HI 258.1493 S 38.75° E IJ
8. Compute for the following and show the tabulated solutions: Azimuth LINES Length (S) АВ 1020.87 168d35m ВС 1117.26 263d30m CD 660.08 304d25m DE 495.85 5d30m EF 850.62 46d15m FA 855.45 112d30m (lengths in 3 dec. places; bearings in deg-mm-ss) a. Using Transit Rule, solve for adjusted latitudes, departures, distances, and bearings for all the traverse lines Lines Adj. Latitude Adj. Departure Adj. Length Adj. Bearing AB BC CD DE EF FA