2. Compute the horizontal force P required to prevent the block from sliding down the plane for the 100 lb block shown. Assume the coefficient of static friction to be 0.65. W=100 lb T 30°

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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**Problem:**

Compute the horizontal force \( P \) required to prevent the block from sliding down the plane for the 100 lb block shown. Assume the coefficient of static friction to be 0.65.

**Diagram Explanation:**

The diagram depicts a block weighing 100 lb placed on an inclined plane. The weight \( W = 100 \, \text{lb} \) acts downwards. A horizontal force \( P \) is applied to the left side of the block, parallel to the plane. The incline of the plane is at an angle of \( 30^\circ \) from the horizontal.

The diagram illustrates the forces acting on the block:
- The weight \( W \) acts vertically downward.
- The applied force \( P \) is horizontal.

The problem requires calculating the magnitude of \( P \) needed to keep the block stationary, preventing it from sliding down due to gravity and friction. The coefficient of static friction is given as 0.65.
Transcribed Image Text:**Problem:** Compute the horizontal force \( P \) required to prevent the block from sliding down the plane for the 100 lb block shown. Assume the coefficient of static friction to be 0.65. **Diagram Explanation:** The diagram depicts a block weighing 100 lb placed on an inclined plane. The weight \( W = 100 \, \text{lb} \) acts downwards. A horizontal force \( P \) is applied to the left side of the block, parallel to the plane. The incline of the plane is at an angle of \( 30^\circ \) from the horizontal. The diagram illustrates the forces acting on the block: - The weight \( W \) acts vertically downward. - The applied force \( P \) is horizontal. The problem requires calculating the magnitude of \( P \) needed to keep the block stationary, preventing it from sliding down due to gravity and friction. The coefficient of static friction is given as 0.65.
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