2. Calculate the AH for the reactionHCl(g) + NaNO₂(s) → HNO₂(1) + NaCl(s)from the following data:2NaCl(s) + H₂O(1)→ 2HCl(g) + Na₂O(s)NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂ (s)NO(g) + NO₂(g) → N₂O(g) + O₂(g)2HNO₂(1)→ N₂O(g) + O₂(g) + H₂O(l)ΔΗ = 507 kJΔΗ = -427 kJΔΗ = -43 kJΔΗ = 34 kJ

Answered: Image /qna-images/answer/a5470b6d-e178-4acf-9678-43e35f050e1a.jpg

2. Calculate the AH for the reaction HCI(g) + NaNO₂(s)→ HNO₂(1) + NaCl(s) from the following data: 2NaCl(s) + H₂O(l) → 2HCl(g) + Na₂O(s) NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂ (s) NO(g) + NO₂(g) → N₂O(g) + O₂(g) 2HNO₂(1)→ N₂O(g) + O₂(g) + H₂O(l) ΔΗ = 507 kJ ΔΗ = -427 kJ ΔΗ = -43 kJ ΔΗ = 34 kJ

2. Calculate the AH for the reaction HCI(g) + NaNO₂(s)→ HNO₂(1) + NaCl(s) from the following data: 2NaCl(s) + H₂O(l) → 2HCl(g) + Na₂O(s) NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂ (s) NO(g) + NO₂(g) → N₂O(g) + O₂(g) 2HNO₂(1)→ N₂O(g) + O₂(g) + H₂O(l) ΔΗ = 507 kJ ΔΗ = -427 kJ ΔΗ = -43 kJ ΔΗ = 34 kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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