2. Below is a table showing the amount of presents wrapped per hour.a) Circle one: EXPONENTIAL / LINEARb) Explain how you know.Time (in hours)Presents wrapped112c) Find the rate of change from 1 to 4 hours.243660d) Find the rate of change from 0 to 5 hours.3. Below is a table showing the gerbil population in a village. Let x represent the number of years and y be thenumber of gerbils.a) Circle one: EXPONENTIAL / LINEARb) Explain how you know.11152.753.375c) Find the rate of change from 0 to 2 years.1,875d) Find the rate of change from 1 to 4 years.4.

Answered: 2. Below is a table showing the amount…

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

2. Below is a table showing the amount of presents wrapped per hour.
a) Circle one: EXPONENTIAL / LINEAR
b) Explain how you know.
Time (in hours)
Presents wrapped
1
12
c) Find the rate of change from 1 to 4 hours.
24
36
60
d) Find the rate of change from 0 to 5 hours.
3. Below is a table showing the gerbil population in a village. Let x represent the number of years and y be the
number of gerbils.
a) Circle one: EXPONENTIAL / LINEAR
b) Explain how you know.
11
15
2.
75
3.
375
c) Find the rate of change from 0 to 2 years.
1,875
d) Find the rate of change from 1 to 4 years.
4.

Expert Solution

Step 1

$a) a n d b) p a r t A f u n c t i o n y = f (x) i s s a i d t o b e t h e l i n e a r f u n c t i o n o f x i . e . y = f (x) = a x + b; a \neq 0 . I n c a s e o f s u c h a l i n e a r f u n c t i o n t h e s l o p e o f t h e l i n e r e p r e s e n t e d b y t h e f u n c t i o n r e m a i n s c o n s \tan t . A n e x p o n e n t i a l f u n c t i o n y = f (x) = a b^{x}; a, b \neq 0 : r e p r e s e n t s t h e g e n e r a l t e r m o f a g e o m e t r i c p r o g r e s s i o n w h i c h g r o w s b y a f a c t o r r e f e r r e d t o a s a c o m m o n r a t i o o f t h e s e r i e s . A f u n c t i o n y = f (x) i s s a i d t o b e t h e l i n e a r f u n c t i o n o f x i . e . y = f (x) = a x + b; a \neq 0 . F o r s u c h a l i n e a r f u n c t i o n t h e s l o p e o f t h e l i n e r e p r e s e n t e d b y t h e f u n c t i o n r e m a i n s c o n s \tan t . A n e x p o n e n t i a l f u n c t i o n y = f (x) = a e b x; a, b \neq 0 r e p r e s e n t s t h e g e n e r a l t e r m o f a g e o m e t r i c p r o g r e s s i o n w h i c h g r o w s b y a f a c t o r r e f e r r e d t o a s a c o m m o n r a t i o o f t h e s e r i e s .$

$\frac{f (1)}{f (0)} = \frac{f (2)}{f (1)} = \frac{f (3)}{f (2)} = \frac{f (4)}{f (3)} = c o m m o n r a t i o$

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