Answer part a Frq style 2. Based on a poll of registered voters in a large city, 120 out of a random sample of 250 women intended to vote for Donald Trump in the 2020 presidential electionand 132 out of a random sample of 240 men intended to vote for Donald Trump.A Is there convincing evidence that there is a difference in the proportion of all women and the proportion of all men in this city who intended to vote for Trumpn inthe 2020 presidential election at the a = 0.05 level?B. Based on your conclusion, what type of error could you have just made? Describe a consequence of making this type of error.Drouious

Answered: 2. Based on a poll of registered voters…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Answer part a Frq style

2. Based on a poll of registered voters in a large city, 120 out of a random sample of 250 women intended to vote for Donald Trump in the 2020 presidential election
and 132 out of a random sample of 240 men intended to vote for Donald Trump.
A Is there convincing evidence that there is a difference in the proportion of all women and the proportion of all men in this city who intended to vote for Trumpn in
the 2020 presidential election at the a = 0.05 level?
B. Based on your conclusion, what type of error could you have just made? Describe a consequence of making this type of error.
Drouious

Expert Solution

Step 1

The total number of women $n_{1} = 250$
The number of women intend to vote Trump $= 120$
The proportion of women vote for Trump $p_{1} = \frac{120}{250} = 0.48$

The total number of men $n_{2} = 240$
The number of women intend to vote Trump $= 132$
The proportion of women vote for Trump $p_{2} = \frac{132}{240} = 0.55$

Level of significance $= 0.05$

The null and alternate hypothesis are
$H_{o} : p_{1} - p_{2} = 0 H_{a} : p_{1} - p_{2} \neq 0$

The pooled sample proportion are calculated as shown below
$p = \frac{n_{1} p_{1} + n_{2} p_{2}}{n_{1} + n_{2}} = \frac{120 + 132}{250 + 240} = 0.5143$

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