2. As capacitors are added in parallel to a circuit, A. capacitive reactance increases B. impedance increases C. capacitance decreases D. capacitive reactance decreases
2. As capacitors are added in parallel to a circuit, A. capacitive reactance increases B. impedance increases C. capacitance decreases D. capacitive reactance decreases
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![### Question:
2. As capacitors are added in parallel to a circuit, _______ .
A. capacitive reactance increases
B. impedance increases
C. capacitance decreases
D. capacitive reactance decreases
### Detailed Explanation:
When capacitors are connected in parallel in a circuit, the total capacitance of the circuit increases. This is because the effective capacitance (C_total) in a parallel connection is the sum of the individual capacitances (C1, C2, C3, etc.). Mathematically:
\[ C_{total} = C_1 + C_2 + C_3 + \cdots + C_n \]
Since capacitance is inversely proportional to capacitive reactance (X_C), an increase in capacitance will result in a decrease in capacitive reactance.
\[ X_C = \frac{1}{2 \pi f C} \]
Where:
- \( X_C \) is the capacitive reactance.
- \( f \) is the frequency of the AC supply.
- \( C \) is the capacitance.
Therefore, the correct answer is:
D. capacitive reactance decreases.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02026046-f334-4297-9417-2971e130f16a%2F93e9001a-1af9-4065-87b3-9d11e3451241%2F9z2xe5r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question:
2. As capacitors are added in parallel to a circuit, _______ .
A. capacitive reactance increases
B. impedance increases
C. capacitance decreases
D. capacitive reactance decreases
### Detailed Explanation:
When capacitors are connected in parallel in a circuit, the total capacitance of the circuit increases. This is because the effective capacitance (C_total) in a parallel connection is the sum of the individual capacitances (C1, C2, C3, etc.). Mathematically:
\[ C_{total} = C_1 + C_2 + C_3 + \cdots + C_n \]
Since capacitance is inversely proportional to capacitive reactance (X_C), an increase in capacitance will result in a decrease in capacitive reactance.
\[ X_C = \frac{1}{2 \pi f C} \]
Where:
- \( X_C \) is the capacitive reactance.
- \( f \) is the frequency of the AC supply.
- \( C \) is the capacitance.
Therefore, the correct answer is:
D. capacitive reactance decreases.
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