2. An electron is instantaneously located at the origin and had a velocity of i = (5.0 x 107,0.0,0.0)m/s. Atthis moment, find the vector magnetic field at the two locations: (3.0,4. 0,0. 0)m and (5.0,0.0,0.0)m.Express your answer as a vector.

The electron is moving with a velocity, given by the equation v≡5×107, 0, 0In vector form, it is represented asv=5×107 i m/s So the electron has a velocity component only along the x direction, hence the electron is moving along the x direction. The magnetic field produced by this electron at any given point in space is given in vector form as B=μo4πqv×rr3 r is the position vector of the given point q is the magnitude of the chargeFor an electron, q=1.6×10-19 C For the first given point, (3, 4, 0) m, the position vector of this point in vector as well as magnitude is r=3i+4jr=32+42r=25r=5 m The magnetic field at this first location is B=μo4πqv×rr3B=4π×10-74π1.6×10-195×107 i×3i+4j53Since, i×i=0 and i×j=kB=10-71.6×10-191254×5×107i×jB=1.28×10-2820×107 kB=2.56×10-20 k T This is the magnetic field at the first location, directed along the z axisAt the next point, (5, 0, 0) m, r=5ir=5 m Thus, B=μo4πqv×rr3B=1.28×10-285×107i×5iAnd since i×i=0Thus, B=0 So there is no magnetic field present at this second locationAnswers: Magnetic field at the first location, B=2.56×10-20 k^ T Magnetic field at the second location, B=0

Answered: 2. An electron is instantaneously…

2. An electron is instantaneously located at the origin and had a velocity of i = (5.0 x 107,0.0,0.0)m/s. At this moment, find the vector magnetic field at the two locations: (3.0, 4. 0, 0. 0)m and (5. 0, 0. 0, 0. 0)m. Express your answer as a vector.