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2. An automobile and its load weigh 22.5 KN and the center of gravity is 0.60 m above ground level and midway between the front and rear wheels, 2.44 m apart. The car is brought to a complete stop from a speed of 96.5 km/hr in 10 seconds by means of the breaks. Find the normal pressures on each of the front and rear wheels. Let NF = normal pressure on one front wheel F= reversed effective force ="a NR = normal pressure on one rear wheel REF 0.60 m 1.22 m 1.22 m 2NR 2N.

2. An automobile and its load weigh 22.5 KN and the center of gravity is 0.60 m above ground level and midway between the front and rear wheels, 2.44 m apart. The car is brought to a complete stop from a speed of 96.5 km/hr in 10 seconds by means of the breaks. Find the normal pressures on each of the front and rear wheels. Let NF = normal pressure on one front wheel F= reversed effective force ="a NR = normal pressure on one rear wheel REF 0.60 m 1.22 m 1.22 m 2NR 2N.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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2. An automobile and its load weigh 22.5 KN and the center of gravity is 0.60 m above ground level and midway between the front and rear wheels, 2.44 m apart. The car is brought to a complete stop from a speed of 96.5 km/hr in 10 seconds by means of the breaks. Find the normal pressures on each of the front and rear wheels. Let NF = normal pressure on one front wheel REF = reversed effective force = a NR = normal pressure on one rear wheel REF 0.60 m R F 1.22 m 1.22 m 2NR 2NF
Transcribed Image Text:2. An automobile and its load weigh 22.5 KN and the center of gravity is 0.60 m above ground level and midway between the front and rear wheels, 2.44 m apart. The car is brought to a complete stop from a speed of 96.5 km/hr in 10 seconds by means of the breaks. Find the normal pressures on each of the front and rear wheels. Let NF = normal pressure on one front wheel REF = reversed effective force = a NR = normal pressure on one rear wheel REF 0.60 m R F 1.22 m 1.22 m 2NR 2NF
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