2. According to the average molar mass your calculated, which one of the following liquids is possibly your unknown sample (show the calculations for how you selected your answer). 1 a. Water H₂O b. Acetone C3H6O c. Cyclohexane C6H12 d. Ethanol C₂H5OH

2. According to the average molar mass your calculated, which one of the following liquids is possibly your unknown sample (show the calculations for how you selected your answer). 1 a. Water H₂O b. Acetone C3H6O c. Cyclohexane C6H12 d. Ethanol C₂H5OH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

R = 0.0821 L.atm/mol.°K
Sample ID: A
Mass of the empty
Erlenmeyer flask +
rubber band + foil
Pressure
Temperature (°C)
Temperature (°K)
Mass of flask + vapor +
rubber band + foil
Mass of vapor (grams)
Volume of Flask
Calculated number of
moles (n)
Molar Mass (g/mol)
Average Molar Mass
(g/mol)
n=
/
107.2189
I atm
95°℃
368.15⁰K
108.209
0.9829
MM-
=
pv
1* 0.33
RT 0.0821 368.15
Trial 1
330ml=0.33L
a. Water H₂O
b. Acetone C3H6O
c. Cyclohexane C6H12
d. Ethanol C₂H5OH
n
=
:0.010 met
0.982
0.010
= 98.29/mol
n=
Trial 2
107.2189
I atm
95.1°C
368.25 k
108.2969
1.0789
330ml=0.33L
pv
RT
MM =
103 g/mol
1*0.33
0.0821368.25
.:0.010 mol
m 1.078
n
0.010
=
2. According to the average molar mass your calculated, which one of the following
liquids is possibly your unknown sample (show the calculations for how you
selected your answer).
=107.89/mol

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