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2. A titration was done with H2SO4 as the analyte in the flask and Al(OH)3 as the titrant in the burette according to this equation: 3 H2SO4(aq) + 2 Al(OH)3(aq) Al2(SO4)3(5) + 6 H2O) ---> If 47.31 mL of 0.09847 M AI(OH)3 was used to neutralize 25.00 mL of H2SO4, what is the molarity of the H2SO4?

2. A titration was done with H2SO4 as the analyte in the flask and Al(OH)3 as the titrant in the burette according to this equation: 3 H2SO4(aq) + 2 Al(OH)3(aq) Al2(SO4)3(5) + 6 H2O) ---> If 47.31 mL of 0.09847 M AI(OH)3 was used to neutralize 25.00 mL of H2SO4, what is the molarity of the H2SO4?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 2** A titration was done with \( \text{H}_2\text{SO}_4 \) as the analyte in the flask and \( \text{Al(OH)}_3 \) as the titrant in the burette according to this equation: \[ 3 \text{H}_2\text{SO}_4 (aq) + 2 \text{Al(OH)}_3 (aq) \rightarrow \text{Al}_2(\text{SO}_4)_3 (s) + 6 \text{H}_2\text{O} (l) \] If 47.31 mL of 0.09847 M \( \text{Al(OH)}_3 \) was used to neutralize 25.00 mL of \( \text{H}_2\text{SO}_4 \), what is the molarity of the \( \text{H}_2\text{SO}_4 \)?
Transcribed Image Text:**Question 2** A titration was done with \( \text{H}_2\text{SO}_4 \) as the analyte in the flask and \( \text{Al(OH)}_3 \) as the titrant in the burette according to this equation: \[ 3 \text{H}_2\text{SO}_4 (aq) + 2 \text{Al(OH)}_3 (aq) \rightarrow \text{Al}_2(\text{SO}_4)_3 (s) + 6 \text{H}_2\text{O} (l) \] If 47.31 mL of 0.09847 M \( \text{Al(OH)}_3 \) was used to neutralize 25.00 mL of \( \text{H}_2\text{SO}_4 \), what is the molarity of the \( \text{H}_2\text{SO}_4 \)?
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