2. A sample of a substance containing only carbon, hydrogen, and oxygen has mass x in grams. It is burned and produces y grams of carbon dioxide and z grams of water. What is the empirical formula of the substance?    Leave your answer as a system of two equations in terms of constants (x, y, z), unknowns (a, b, c), and atomic masses from the periodic table. (no point in giving you numbers for x, y, z or having you do linear algebra – get used to variables!)    Hint: Write the chemical equation giving your carbohydrate subscripts a for C, b for H, and c for O.    Hint: Find the coefficients of this equation in terms of a, b, and c. For now, leave the coefficient of the hydrocarbon 1.    Hint: One equation will have ratios between the carbohydrate and carbon dioxide; the other, ratios between the carbohydrate and water.

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2. A sample of a substance containing only carbon, hydrogen, and oxygen has mass x in grams. It is burned and produces y grams of carbon dioxide and z grams of water. What is the empirical formula of the substance?

   Leave your answer as a system of two equations in terms of constants (x, y, z), unknowns (a, b, c), and atomic masses from the periodic table. (no point in giving you numbers for x, y, z or having you do linear algebra – get used to variables!)

   Hint: Write the chemical equation giving your carbohydrate subscripts a for C, b for H, and c for O.

   Hint: Find the coefficients of this equation in terms of a, b, and c. For now, leave the coefficient of the hydrocarbon 1.

   Hint: One equation will have ratios between the carbohydrate and carbon dioxide; the other, ratios between the carbohydrate and water.

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The equation for the burning of carbohydrate is:

x12a+b+16c CaHbOc  +  O2       y44CO2  +  Z18 H2OThe stoichiometric coefficients are calculated as per the given masses.Now, consider the burning of a carbohydrateC6H12O6  + 6 O2       6CO2  +  6 H2OC12H22O11  + 12 O2       12CO2  +   11H2OThe coefficients are in a pattern, always, such thatcoefficient of CO2=O2= No. of cabon atomscoefficient of H2O = No. of Oxygen atoms in hydrocarbon= 12no of Hydrogen atomsHence,     y44=aZ18= c=b2

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