2. A rope connect two masses, M₁-8 kg. and M₂-5 kg. They are initially held at the same height above the ground, h=1.5 m, with the left (larger) mass connected by a spring to the ground. When the masses are released, M₁ goes down 25 m, and M₂ goes up 25 m The spring is initially uncompressed. Both masses are initially and finally at rest. The objective of this problem is to find the value of k for this spring using conservation of energy

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Chapter1: Units, Trigonometry. And Vectors
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2. A rope connect two masses, M₁ - 8 kg.. and M₂ = 5 kg. They are initially held at the same height
above the ground, h, = 1.5 m, with the left (larger) mass connected by a spring to the ground.
When the masses are released, M₁ goes down 25 m, and M₂ goes up 25 m.
The spring is initially uncompressed. Both masses are initially and finally at rest.
The objective of this problem is to find the value of k for this spring using conservation of energy.
M₁
h = 1.5m
a. What are the values of the initial potential energies of each mass and the spring?
Get numbers for each of these.
M₁: PE
M₂: PE
Spring: PEsp=
PE=
M₂
・117.6
73.5
0
KE₂ =
E₁ =
191.1
0
191.1
b. What are the TOTAL PE,, KE,, and E?
Get numbers for each of these.
Joules
Joules
Joules
Joules
Joules
Joules
M₁
hy-1.25 m
M₂
by-1.75 m
c. What are the values of the final potential energies of each mass and the spring?
_98.0
M₁ PEg=
Joules
M₂: PEgr - 85.75 Joules
Spring: PEspy-0-03125 This answer will be in terms of k.
d. What are the TOTAL PE, KE, and E?
183.75 + 0.03125 Joules
KE= O
Joules
E₁-183.75 +0.03125 Joules
NOTE: Some of these answers will also be in terms of k
e. Use conservation of energy to solve for k
PE=1
k=235.2
f. Determine the work for each of the following When calculating work, remember to consider to til
direction of the force and the direction of the displacement.
W₁₁. 19.6
Joules
Joules
W₁₂--12.25
-7.35
0
W
W
N/m
Joules
Transcribed Image Text:2. A rope connect two masses, M₁ - 8 kg.. and M₂ = 5 kg. They are initially held at the same height above the ground, h, = 1.5 m, with the left (larger) mass connected by a spring to the ground. When the masses are released, M₁ goes down 25 m, and M₂ goes up 25 m. The spring is initially uncompressed. Both masses are initially and finally at rest. The objective of this problem is to find the value of k for this spring using conservation of energy. M₁ h = 1.5m a. What are the values of the initial potential energies of each mass and the spring? Get numbers for each of these. M₁: PE M₂: PE Spring: PEsp= PE= M₂ ・117.6 73.5 0 KE₂ = E₁ = 191.1 0 191.1 b. What are the TOTAL PE,, KE,, and E? Get numbers for each of these. Joules Joules Joules Joules Joules Joules M₁ hy-1.25 m M₂ by-1.75 m c. What are the values of the final potential energies of each mass and the spring? _98.0 M₁ PEg= Joules M₂: PEgr - 85.75 Joules Spring: PEspy-0-03125 This answer will be in terms of k. d. What are the TOTAL PE, KE, and E? 183.75 + 0.03125 Joules KE= O Joules E₁-183.75 +0.03125 Joules NOTE: Some of these answers will also be in terms of k e. Use conservation of energy to solve for k PE=1 k=235.2 f. Determine the work for each of the following When calculating work, remember to consider to til direction of the force and the direction of the displacement. W₁₁. 19.6 Joules Joules W₁₂--12.25 -7.35 0 W W N/m Joules
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