only number 2 Problems:1. Load the audio file "washington". Use 8kHz as the sampling rate. Then, createx₁ [n] = {0.5 if x[n] < 0if x[n] ≥ 0Where x[n] is the input speech signal (Washington). Play x₁ [n] and comment on the quality ofthe speech signal. (You may use function "audioread" to read the audio and "sound" to play theaudio in MATLAB.).2. a) Quantize x[n] to 4 levels using a uniform quantizer.1,y[n] = Q(x[n]) = . 0,0.5,y[n] = Q(x[n])Can you understand y[n]?c) Explain the difference-1,Can you understand y[n]?b) Now consider the following 4-level quantizer1,x[n] ≥ 0.50.25 ≤ x[n] < 0.5-0.25 ≤ x[n] < 0.25x[n] -0.250.5,0,-1,x[n] ≥ 0.50 ≤ [n] < 0.5-0.5 ≤ x[n] < 0x[n] < -0.53. a) Plot a segment of "a" of your "Washington". Is it almost periodic? Why?b) Can you identify "sh" sound? Is it periodic?4. Calculate the mean value of your x[n] ("Washington"). Is it close to zero?

Answered: Image /qna-images/answer/01e9c09f-c2b2-431e-b66e-662c23558c65.jpg

2. a) Quantize x[n] to 4 levels using a uniform quantizer. 1, y[n] = Q(x[n]) = 0.5, 0, y[n] = Q(x[n]) = Can you understand y[n]? c) Explain the difference -1, Can you understand y[n]? b) Now consider the following 4-level quantizer 1, x[n] ≥ 0.5 0.25 ≤ x[n] < 0.5 -0.25 ≤ x[n] < 0.25 x[n]<-0.25 0.5, 0, -1, x[n] ≥ 0.5 0 [n] < 0.5 -0.5 ≤ x[n]<0 x[n]<-0.5

2. a) Quantize x[n] to 4 levels using a uniform quantizer. 1, y[n] = Q(x[n]) = 0.5, 0, y[n] = Q(x[n]) = Can you understand y[n]? c) Explain the difference -1, Can you understand y[n]? b) Now consider the following 4-level quantizer 1, x[n] ≥ 0.5 0.25 ≤ x[n] < 0.5 -0.25 ≤ x[n] < 0.25 x[n]<-0.25 0.5, 0, -1, x[n] ≥ 0.5 0 [n] < 0.5 -0.5 ≤ x[n]<0 x[n]<-0.5

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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