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2. A population of birds contains 16 animals with red tail feathers and 34 animals with blue tail feathers. Blue tail feathers are the dominant trait. Red a. What is the frequency of the red allele? 1. Recesive. geke 9. 0.32 95 0= b. What is the frequency of the blue allele? + 0.56 =| (Bluc) 6.49 c. What is the frequency of heterozygotes? 2 pa = 2( 44 (056) 0.49 d. What is the frequency of birds homozygous for the blue allele? O19

2. A population of birds contains 16 animals with red tail feathers and 34 animals with blue tail feathers. Blue tail feathers are the dominant trait. Red a. What is the frequency of the red allele? 1. Recesive. geke 9. 0.32 95 0= b. What is the frequency of the blue allele? + 0.56 =| (Bluc) 6.49 c. What is the frequency of heterozygotes? 2 pa = 2( 44 (056) 0.49 d. What is the frequency of birds homozygous for the blue allele? O19

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Illustrate (Draw) the following using the punnett square method: 

2. A population of birds contains 16 animals with red tail feathers and 34 animals with blue tail feathers. Blue tail feathers are the dominant trait. a. What is the frequency of the red allele? Red % Recesive O12 geke = lo 56 b. What is the frequency of the blue allele? + 0.56 = | (Bluc) 6.44 c. What is the frequency of heterozygotes? 2 pa * 2(P 44(0 56) 0.49 d. What is the frequency of birds homozygous for the blue allele? 019
Transcribed Image Text:2. A population of birds contains 16 animals with red tail feathers and 34 animals with blue tail feathers. Blue tail feathers are the dominant trait. a. What is the frequency of the red allele? Red % Recesive O12 geke = lo 56 b. What is the frequency of the blue allele? + 0.56 = | (Bluc) 6.44 c. What is the frequency of heterozygotes? 2 pa * 2(P 44(0 56) 0.49 d. What is the frequency of birds homozygous for the blue allele? 019
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