2. A limousine service has three cars (sedans) which it hires out by the day. The number of requests for these sedans, per day, is a Poisson random variable, (X), with mean 1.5. a. Complete the following Probability Distribution Table. Report your probabilities to 4 dp. P(X=x) 1 3. 4 b. What is the probability that the firm is able to meet the demand for its cars? c. What is the probability of at least one car requested on a randomly selected day? d. Graph the probability distribution found in (a) and describe its shape.
2. A limousine service has three cars (sedans) which it hires out by the day. The number of requests for these sedans, per day, is a Poisson random variable, (X), with mean 1.5. a. Complete the following Probability Distribution Table. Report your probabilities to 4 dp. P(X=x) 1 3. 4 b. What is the probability that the firm is able to meet the demand for its cars? c. What is the probability of at least one car requested on a randomly selected day? d. Graph the probability distribution found in (a) and describe its shape.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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provide hand written answer for part d asap
Transcribed Image Text:2. A limousine service has three cars (sedans) which it hires out by the day. The
number of requests for these sedans, per day, is a Poisson random variable, (X),
with mean 1.5.
a. Complete the following Probability Distribution Table. Report your
probabilities to 4 dp.
P(X=x)
4
b.
What is the probability that the firm is able to meet the demand for its
cars?
c. What is the probability of at least one car requested on a randomly
selected day?
d. Graph the probability distribution found in (a) and describe its shape.
1.5'c15
= 6, 2231
01
= 0,3347
2.
= 0.2510
21
1.5 e5
31
= 0.1285
1,5 e
31-
= 0.04706
41
= 0.01411
51.
6.
6.
1.3015
0.0003529
l0.0035
1.515
= 0.000 S29
0.0008
x0123 567
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