NameChapter 24 Thermodynamics.Carnot EfficiencyA 25-kW heat engine operates between a 3200-K hot reservoir and a 450-Kcold reservoir. What is the engine's Carnot, or ideal, efficiency?Read and UnderstandWhat information are you given?Power of engine = 25 kWHigh-temperature reservoir, Thot = 3200 KLow-temperature reservoir, Tcold = 450 KPlan and SolveWhat unknown are you trying to calculate?Carnot efficiency = ?What formula contains the given quantity and the unknown?Carnot efficiency =Thot-TooldThotSubstitute the known values and solve.Note that because the hot and cold reservoir temperatures are given inkelvins, they can be directly substituted into the equation.Carnot efficiency - Thot-Teold 3200 K-450 K = 0.86 or 86%=Thot3200 K=Y2. A heat engine has an efficiency of 52% when it runs with a hot-reservoirtemperature of 400°C and cold-reservoir temperature of 50°C. What isthe efficiency if the hot-reservoir temperature is raised to 800°C?204 Conceptual Physics Reading and Study Workbook.Chapter 24ChS

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2. A heat engine has an efficiency of 52% when it runs with a hot-reservoir temperature of 400°C and cold-reservoir temperature of 50°C. What is the efficiency if the hot-reservoir temperature is raised to 800°C?

2. A heat engine has an efficiency of 52% when it runs with a hot-reservoir temperature of 400°C and cold-reservoir temperature of 50°C. What is the efficiency if the hot-reservoir temperature is raised to 800°C?

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Name
Chapter 24 Thermodynamics.
Carnot Efficiency
A 25-kW heat engine operates between a 3200-K hot reservoir and a 450-K
cold reservoir. What is the engine's Carnot, or ideal, efficiency?
Read and Understand
What information are you given?
Power of engine = 25 kW
High-temperature reservoir, Thot = 3200 K
Low-temperature reservoir, Tcold = 450 K
Plan and Solve
What unknown are you trying to calculate?
Carnot efficiency = ?
What formula contains the given quantity and the unknown?
Carnot efficiency =
Thot-Toold
Thot
Substitute the known values and solve.
Note that because the hot and cold reservoir temperatures are given in
kelvins, they can be directly substituted into the equation.
Carnot efficiency - Thot-Teold 3200 K-450 K = 0.86 or 86%
=
Thot
3200 K
=
Y
2. A heat engine has an efficiency of 52% when it runs with a hot-reservoir
temperature of 400°C and cold-reservoir temperature of 50°C. What is
the efficiency if the hot-reservoir temperature is raised to 800°C?
204 Conceptual Physics Reading and Study Workbook.
Chapter 24
Ch
S

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