Kindly provide the solution to the following question using the GRASS method. Electric Fields - Proton / Drop of Oil question, (Unit: Gravitational, Electric, and Magnetic Fields). The images attached are the formulas for this unit and the question. Please make sure to show all your work using the GRASS (given, required, analysis, solution, and statement) method and using formulas from this unit (Gravitational, Electric, and Magnetic Fields). GravitationalGMr²gEg=-GMmrFEElectric FieldsEE=ε =EEkq192d²=FEqkq192ε == dFieldsVorbitalEE kqqd||=dUnit 3 Gravitational, Electric, & Magnetic Fields= qεW = ΔΕ =kq192= qVdqAVΔΕGMT=r³ = CT² Cs(-GMM) - (~GMM)Magnetic FieldsFB = qvBsineFB = Il B sin0=GM47²GMmp2Vescape=2GM 2. A drop of oil is floating between two parallel plates with a separation of 4.0 mm and anapplied voltage of 125 V. If the mass of the oil drop is 3.5 x 10-¹0 kg, determine the charge on thedrop if the top plate is negative. (Hint: The electric force and the force of gravity balance.)

Answered: Image /qna-images/answer/9a4a2a83-4dfd-4120-801f-f8a00cd676f0.jpg

Answered: 2. A drop of oil is floating between…

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

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Kindly provide the solution to the following question using the GRASS method. Electric Fields - Proton / Drop of Oil question, (Unit: Gravitational, Electric, and Magnetic Fields).

The images attached are the formulas for this unit and the question. Please make sure to show all your work using the GRASS (given, required, analysis, solution, and statement) method and using formulas from this unit (Gravitational, Electric, and Magnetic Fields).

Gravitational
GM
r²
g
Eg
=
-GMm
r
FE
Electric Fields
EE
=
ε =
EE
kq192
d²
=
FE
q
kq192
ε =
= d
Fields
Vorbital
EE kq
q
d
||
=
d
Unit 3 Gravitational, Electric, & Magnetic Fields
= qε
W = ΔΕ =
kq192
= qV
d
qAV
ΔΕ
GM
T
=
r³ = CT² Cs
(-GMM) - (~GMM)
Magnetic Fields
FB = qvBsine
FB = Il B sin0
=
GM
47²
GMm
p2
Vescape
=
2GM

2. A drop of oil is floating between two parallel plates with a separation of 4.0 mm and an
applied voltage of 125 V. If the mass of the oil drop is 3.5 x 10-¹0 kg, determine the charge on the
drop if the top plate is negative. (Hint: The electric force and the force of gravity balance.)

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