2. A charged body, moving with a velocity of 8.0 x 10 m/s at an angle of 30 degrees with respect to the magnetic field of strength 5.6 x 10 T, experiences a force of 0.00002 N. What is the magnitude of the charge? a. 8.9 µC b. 5.15 µC c. 3.7 µC d. none
2. A charged body, moving with a velocity of 8.0 x 10 m/s at an angle of 30 degrees with respect to the magnetic field of strength 5.6 x 10 T, experiences a force of 0.00002 N. What is the magnitude of the charge? a. 8.9 µC b. 5.15 µC c. 3.7 µC d. none
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question 2
![**Physics Problem Set: Magnetic Forces and Charged Bodies**
**Problem 1: Proton in a Magnetic Field**
A proton is entering a magnetic field \( \mathbf{B} = 0.2 \mathbf{i} - 0.5 \mathbf{j} + 0.4 \mathbf{k} \). If the proton moves at \( \mathbf{v} = (4000 \mathbf{i} + 5000 \mathbf{k}) \) meters per second, calculate the force vector acting on the proton. The charge of a proton is \( 1.6 \times 10^{-19} \) C.
Options:
- a. \( \mathbf{F} = (4000 \mathbf{i} + 960 \mathbf{j} - 3200 \mathbf{k}) \times 10^{-19} \) N
- b. \( \mathbf{F} = (4000 \mathbf{i} - 960 \mathbf{j} + 3200 \mathbf{k}) \times 10^{-19} \) N
- c. \( \mathbf{F} = (4000 \mathbf{i} - 960 \mathbf{j} - 3200 \mathbf{k}) \times 10^{-19} \) N
- d. \( \mathbf{F} = (4000 \mathbf{i} + 960 \mathbf{j} + 3200 \mathbf{k}) \times 10^{-19} \) N
**Problem 2: Charged Body in a Magnetic Field**
A charged body, moving with a velocity of \( 8.0 \times 10^4 \) m/s at an angle of 30 degrees with respect to a magnetic field of strength \( 5.6 \times 10^{-5} \) T, experiences a force of \( 0.00002 \) N. What is the magnitude of the charge?
Options:
- a. 8.9 μC
- b. 5.15 μC
- c. 3.7 μC
- d. none
**Additional Info: Proton Beam Dynamics**
A beam of protons moves in a circle of radius 0.55 m. The protons move perpendicular to a 0.030 T magnetic field. The mass of a proton is \( 1.67 \times 10^{-27} \) kg. The charge of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F366fde98-e986-4900-b8c3-3945c69e5ca7%2Fc25a9f77-5313-4c8d-a069-95a4dea9d1f5%2F1aqyqrq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Problem Set: Magnetic Forces and Charged Bodies**
**Problem 1: Proton in a Magnetic Field**
A proton is entering a magnetic field \( \mathbf{B} = 0.2 \mathbf{i} - 0.5 \mathbf{j} + 0.4 \mathbf{k} \). If the proton moves at \( \mathbf{v} = (4000 \mathbf{i} + 5000 \mathbf{k}) \) meters per second, calculate the force vector acting on the proton. The charge of a proton is \( 1.6 \times 10^{-19} \) C.
Options:
- a. \( \mathbf{F} = (4000 \mathbf{i} + 960 \mathbf{j} - 3200 \mathbf{k}) \times 10^{-19} \) N
- b. \( \mathbf{F} = (4000 \mathbf{i} - 960 \mathbf{j} + 3200 \mathbf{k}) \times 10^{-19} \) N
- c. \( \mathbf{F} = (4000 \mathbf{i} - 960 \mathbf{j} - 3200 \mathbf{k}) \times 10^{-19} \) N
- d. \( \mathbf{F} = (4000 \mathbf{i} + 960 \mathbf{j} + 3200 \mathbf{k}) \times 10^{-19} \) N
**Problem 2: Charged Body in a Magnetic Field**
A charged body, moving with a velocity of \( 8.0 \times 10^4 \) m/s at an angle of 30 degrees with respect to a magnetic field of strength \( 5.6 \times 10^{-5} \) T, experiences a force of \( 0.00002 \) N. What is the magnitude of the charge?
Options:
- a. 8.9 μC
- b. 5.15 μC
- c. 3.7 μC
- d. none
**Additional Info: Proton Beam Dynamics**
A beam of protons moves in a circle of radius 0.55 m. The protons move perpendicular to a 0.030 T magnetic field. The mass of a proton is \( 1.67 \times 10^{-27} \) kg. The charge of
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