2. A carnival game is played as follows: You draw a card from an ordinary deck. If you draw an ace, you win $5. You win $3 for a picture card and $10 for the three of spades. If you pick anything else, you lose $2. On average, how much money can the operator expect to make per customer? x | P(x) -S -3 ㅇ -10 x· P(x) 4/52 -20/52 12/52 -36/52 Expected value = M 1/52-10/2 2 35/52 X = the amount gain / loss of the operator 70/52 4/52 Σ [x-P(x)] 4/52 ~³0.08

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.1: Adding And Subtracting Polynomials
Problem 58PPS
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I am confused on how they got the numbers for the table. Can you explain it in a easy way that is not extremely long, thanks!

2. A carnival game is played as follows: You draw a card from an ordinary deck. If you draw an
ace, you win $5. You win $3 for a picture card and $10 for the three of spades. If you pick
anything else, you lose $2. On average, how much money can the operator expect to make per
customer?
x | P(x) = x· P(x)
4/52-20/52
-S
- 3
-10
2
X = the amount gain / loss of
the operator
12/52 -36/52 Expected value = M
1/52-10/52
35/52 70/52
4/52
=
Σ [x. P(x)]
4/52
0.08
Transcribed Image Text:2. A carnival game is played as follows: You draw a card from an ordinary deck. If you draw an ace, you win $5. You win $3 for a picture card and $10 for the three of spades. If you pick anything else, you lose $2. On average, how much money can the operator expect to make per customer? x | P(x) = x· P(x) 4/52-20/52 -S - 3 -10 2 X = the amount gain / loss of the operator 12/52 -36/52 Expected value = M 1/52-10/52 35/52 70/52 4/52 = Σ [x. P(x)] 4/52 0.08
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