2. A 4.626 milligram sample of a hydrocarbon, upon combustion in a combustion analysis apparatus, yielded 12.693 milligrams of carbon dioxide FW:44.01). From this data, the percent carbon by mass was determined to be 74.88. What is the empirical formula of this compound? Note: Hydrocarbons contain only carbon and hydrogen atoms. A. C₂H3 B. CH3 C. CH4 D. CH E. CH₂

2. A 4.626 milligram sample of a hydrocarbon, upon combustion in a combustion analysis apparatus, yielded 12.693 milligrams of carbon dioxide FW:44.01). From this data, the percent carbon by mass was determined to be 74.88. What is the empirical formula of this compound? Note: Hydrocarbons contain only carbon and hydrogen atoms. A. C₂H3 B. CH3 C. CH4 D. CH E. CH₂

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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please answer quickly thanks for the help in advance