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2. 60.0 mL of 0.322 M Potassium lodide (Pbl2) are combined with 20.0 mL of 0.530 M lead (II) nitrate (Pb(NO3)2). How many grams of Lead (II) lodide will be produced? Equation: KI Pbl2 + Pb(NO3)2 ->> KNO3 +

2. 60.0 mL of 0.322 M Potassium lodide (Pbl2) are combined with 20.0 mL of 0.530 M lead (II) nitrate (Pb(NO3)2). How many grams of Lead (II) lodide will be produced? Equation: KI Pbl2 + Pb(NO3)2 ->> KNO3 +

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answer question number 2 only.

Instruction: Solve the following problem in Solution of Stoichiometry. Show all the calculation and derivations. (Note: Late paper submission will be deducted by 5 points.) 1. Calculate the grams of silver chloride (A9CI) produced from 10.00 ml of 10.0M magnesium chloride (MgCl2) with 100.0 ml of 2.20 M silver nitrate (AGNO3) Equation: 2A9NO3 + MgCl2 ->> Mg(N03)2 + 2A9CI 2. 60.0 mL of 0.322 M Potassium lodide (Pbl2) are combined with 20.0 mL of 0.530 M lead (II) nitrate (Pb(NO3)2). How many grams of Lead (II) lodide will be produced? Equation: KI + Pbl2 Pb(NO3)2 ->> KNO3
Transcribed Image Text:Instruction: Solve the following problem in Solution of Stoichiometry. Show all the calculation and derivations. (Note: Late paper submission will be deducted by 5 points.) 1. Calculate the grams of silver chloride (A9CI) produced from 10.00 ml of 10.0M magnesium chloride (MgCl2) with 100.0 ml of 2.20 M silver nitrate (AGNO3) Equation: 2A9NO3 + MgCl2 ->> Mg(N03)2 + 2A9CI 2. 60.0 mL of 0.322 M Potassium lodide (Pbl2) are combined with 20.0 mL of 0.530 M lead (II) nitrate (Pb(NO3)2). How many grams of Lead (II) lodide will be produced? Equation: KI + Pbl2 Pb(NO3)2 ->> KNO3
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