2.4.6.19. GIVEN: DC bisects ZACB; 23 24PROVE: ZA ZB1. DC bisects ZACB3. 41 425. AACD ASTATEMENTS1.2. Given3.5.C6.3 4D4. Reflexive PropertyBREASONS

Answered: Image /qna-images/answer/221a8eef-af17-44a6-8e19-9164afa747e8.jpg

Answered: 2. 4. 6. 19. GIVEN: DC bisects ZACB; 23…

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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10. Justify the last two steps of the proof. * Given: AB = DC and AC = DB Prove: AABC = ADCB B D Proof: 1. AB = DC 1. Given 2. AC = DB 2. Given 3. ? 4. ? 3. BC = CB 4. AABC = ADCB Transitive Property of Congruence; SSS Postulate O Symmetric Property of Congruence; sSS Postulate Transitive Property of Congruence; SAS Postulate Symmetric Property of Congruence; SAS Postulate
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2. 4. 6. 19. GIVEN: DC bisects ZACB; 23 = 24 PROVE: ZA ZB 1. DC bisects ZACB 3. 21 22 5. AACD A STATEMENTS 1. 2. Given A 5. 6. 3 4 D 3. 4. Reflexive Property B REASONS