2. 25.00 mL of Saturated solution of KHTar that contained 0.10 M NaCl: NaOH Volumes: Final 46.30 mL _21.15. _mL mL 0.0500 M NaOH Initial 30.30 5.05 Used Average Used mL
2. 25.00 mL of Saturated solution of KHTar that contained 0.10 M NaCl: NaOH Volumes: Final 46.30 mL _21.15. _mL mL 0.0500 M NaOH Initial 30.30 5.05 Used Average Used mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![2. 25.00 mL of Saturated solution of KHTar that contained 0.10 M NaCl:
NaOH Volumes:
Final _46.30_
_mL_21.15
mL
mL
0.0500 M NаОН
Initial
_30.30
5.05
Used
Average Used
mL
Solubility-2
2
Show your method to calculate the [HTar], [K*] and the solubility of KHTar in the 0.10 M NaCl.
(Don't forget the chemical reaction that occurred).
[HTar] =
[K*] =
KHTar solubility =
(moles/L)
Calculate the Kp value for KHTar in this solution.
Ksp
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffcdebce5-c040-4b4f-93b5-eb08d9483636%2F7b564692-7041-4443-a073-f5da37b7fe65%2Fi5um5ml_processed.png&w=3840&q=75)
Transcribed Image Text:2. 25.00 mL of Saturated solution of KHTar that contained 0.10 M NaCl:
NaOH Volumes:
Final _46.30_
_mL_21.15
mL
mL
0.0500 M NаОН
Initial
_30.30
5.05
Used
Average Used
mL
Solubility-2
2
Show your method to calculate the [HTar], [K*] and the solubility of KHTar in the 0.10 M NaCl.
(Don't forget the chemical reaction that occurred).
[HTar] =
[K*] =
KHTar solubility =
(moles/L)
Calculate the Kp value for KHTar in this solution.
Ksp
II
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