Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 25 of 30**
*Problem Statement:*
300.0 mL of a 0.300 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?
*Solution:*
To find the new concentration after dilution, use the formula:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) is the initial concentration (0.300 M)
- \( V_1 \) is the initial volume (300.0 mL)
- \( C_2 \) is the final concentration
- \( V_2 \) is the final volume (700.0 mL)
Rearrange to solve for \( C_2 \):
\[ C_2 = \frac{C_1V_1}{V_2} = \frac{0.300 \times 300.0}{700.0} \]
Perform the calculation to find \( C_2 \).
(Note: A number pad with numeric keys and basic operation symbols is displayed below the text to enable user input. Additionally, there is a button for clearing input and one for entering exponentially large numbers.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a85ba4d-6f5c-41bf-97e5-182adb23b838%2Fc889f0bd-b03f-4d6d-bb58-38b6083e200b%2Fmy0e0n_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 25 of 30**
*Problem Statement:*
300.0 mL of a 0.300 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?
*Solution:*
To find the new concentration after dilution, use the formula:
\[ C_1V_1 = C_2V_2 \]
Where:
- \( C_1 \) is the initial concentration (0.300 M)
- \( V_1 \) is the initial volume (300.0 mL)
- \( C_2 \) is the final concentration
- \( V_2 \) is the final volume (700.0 mL)
Rearrange to solve for \( C_2 \):
\[ C_2 = \frac{C_1V_1}{V_2} = \frac{0.300 \times 300.0}{700.0} \]
Perform the calculation to find \( C_2 \).
(Note: A number pad with numeric keys and basic operation symbols is displayed below the text to enable user input. Additionally, there is a button for clearing input and one for entering exponentially large numbers.)
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