2. 0.450mol of a gas at 300K occupies a volume of 0.650L. What is the pressure?

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Chapter1: Chemical Foundations
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### Problem 2:
**Given:**
- Amount of gas: \( 0.450 \text{ mol} \)
- Temperature: \( 300 \text{ K} \)
- Volume: \( 0.650 \text{ L} \)

**Question:**
What is the pressure?

---

This problem involves applying the Ideal Gas Law to find the pressure of a gas given the volume, temperature, and number of moles of the gas. 

The Ideal Gas Law is expressed as:
\[ PV = nRT \]

Where:
- \( P \) is the pressure
- \( V \) is the volume
- \( n \) is the number of moles
- \( R \) is the ideal gas constant (\( 0.0821 \text{ L·atm·K}^{-1}\text{·mol}^{-1} \))
- \( T \) is the temperature in Kelvin

You can solve for the pressure \( P \) using the equation:

\[ P = \frac{nRT}{V} \]

By substituting the given values into the equation, you can find the pressure of the gas.
Transcribed Image Text:### Problem 2: **Given:** - Amount of gas: \( 0.450 \text{ mol} \) - Temperature: \( 300 \text{ K} \) - Volume: \( 0.650 \text{ L} \) **Question:** What is the pressure? --- This problem involves applying the Ideal Gas Law to find the pressure of a gas given the volume, temperature, and number of moles of the gas. The Ideal Gas Law is expressed as: \[ PV = nRT \] Where: - \( P \) is the pressure - \( V \) is the volume - \( n \) is the number of moles - \( R \) is the ideal gas constant (\( 0.0821 \text{ L·atm·K}^{-1}\text{·mol}^{-1} \)) - \( T \) is the temperature in Kelvin You can solve for the pressure \( P \) using the equation: \[ P = \frac{nRT}{V} \] By substituting the given values into the equation, you can find the pressure of the gas.
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