2. 0.405 g of CaCO3 is dissolved in HCl and diluted to a volume of 250.00 mL. What is the molarity of calcium ions in the solution? You can use the following steps to solve the problem: a. Determine the molar mass of CaCO3 b. Determine the mole of 0.405 g of CaCO3 c. Determine the solution volume in Liter d. Use the mole of the solute (Ca²+) and the volume of the solution to determine the molarity of calcium ions

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Solve Q2. All subparts solution need. (Gpt/Ai wrong ans not allowed)
2. 0.405 g of CaCO3 is dissolved in HCl and diluted to a volume of 250.00 mL. What is the
molarity of calcium ions in the solution? You can use the following steps to solve the
problem:
a. Determine the molar mass of CaCO3
b. Determine the mole of 0.405 g of CaCO3
c. Determine the solution volume in Liter
d. Use the mole of the solute (Ca²+) and the volume of the solution to determine the
molarity of calcium ions
3. A 25.00 mL aliquot (a portion or part) of the calcium solution prepared in Question 2
reacts with 27.25mL of the EDTA solution. What is the molarity of the EDTA? Show
your work. The reaction equation of EDTA and calcium ion is,
Ca²+ + H₂EDTA² → CaEDTA²+ + 2H+
Transcribed Image Text:2. 0.405 g of CaCO3 is dissolved in HCl and diluted to a volume of 250.00 mL. What is the molarity of calcium ions in the solution? You can use the following steps to solve the problem: a. Determine the molar mass of CaCO3 b. Determine the mole of 0.405 g of CaCO3 c. Determine the solution volume in Liter d. Use the mole of the solute (Ca²+) and the volume of the solution to determine the molarity of calcium ions 3. A 25.00 mL aliquot (a portion or part) of the calcium solution prepared in Question 2 reacts with 27.25mL of the EDTA solution. What is the molarity of the EDTA? Show your work. The reaction equation of EDTA and calcium ion is, Ca²+ + H₂EDTA² → CaEDTA²+ + 2H+
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