2-y'-1 x-1 3 If f(x, y) = ,x + 1 ,x = 1 then f, (1,0) – 2f:(1,0) = x3 -y3 -1 If f(x, y) , X 7 1 x-1 3 ,x = 1 then fy(1,0) – 2 f (1,0) = O -6 O-9 0 6 does not exist AUG 12 étv MacBook Air F4 F5 F6 F7 F8 F9 F10 2$ & 5 0 6 7 8 A 94 R Y P 20

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A: This question is based on Partial Derivative.

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A: Detailed explanation mentioned below

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