人 108+87=540 7x+19735440 7x=343 メニ49 2X 3x LA =82

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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#19 please

人 108+87=540
7x+19735440
7x=343
メニ49
2X
3x
LA =82
<Eニ108
LB= 2x+7=105
LCニ34タ214プ
LD=2.49=9
17) mZ3=(2x- 6)(x-4)
mZ5= 5(5x + 3)- (2x2-42)
Determine the value of x so that line / will be parallel to line m.
3/4 2
ら クm
घड
1/8
m<3+m<5z1800
(2x-6)(x-4)+5(5x+3)-(2x242)-120
2入ー8x-6x+24+25x+15-2x42=120
イメニ180-81
月メニタタ
メこす
18) Given: XM bisects YXZ and ZYMZ.
Prove: XM bisects ZYKZ
statements
reasons
1)XM bisects Yx2 YME Gven
M.
19) Given: PS = RQ; PQ = RS Prove: PQ || SR
reasons
statements
PCRQ POE RS Aver
Transcribed Image Text:人 108+87=540 7x+19735440 7x=343 メニ49 2X 3x LA =82 <Eニ108 LB= 2x+7=105 LCニ34タ214プ LD=2.49=9 17) mZ3=(2x- 6)(x-4) mZ5= 5(5x + 3)- (2x2-42) Determine the value of x so that line / will be parallel to line m. 3/4 2 ら クm घड 1/8 m<3+m<5z1800 (2x-6)(x-4)+5(5x+3)-(2x242)-120 2入ー8x-6x+24+25x+15-2x42=120 イメニ180-81 月メニタタ メこす 18) Given: XM bisects YXZ and ZYMZ. Prove: XM bisects ZYKZ statements reasons 1)XM bisects Yx2 YME Gven M. 19) Given: PS = RQ; PQ = RS Prove: PQ || SR reasons statements PCRQ POE RS Aver
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