Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 2 of the attachment. If you could show the work that would be helpful.

Transcribed Image Text:### Calculus Integration Problems
Here are a set of integral problems that can be used for practice in an educational setting. They vary in difficulty and cover a range of integral types.
1. \(\int (2 - x^2)^4 \; dx\)
2. \(\int \frac{x \; dx}{9 + x^2}\)
3. \(\int \frac{x^2 - 5x + 6 \; dx}{x^3 - 2x^2 + x}\)
4. \(\int x e^{\frac{3}{5} x} \; dx\)
5. \(\int x^3 \ln x \; dx\)
6. \(\int \cos 5x \sin 9x \; dx\)
7. \(\int \tan^4 \left( \frac{5}{x} \right) \; dx\)
### Explanations and Graphs (if applicable)
Each integral challenges the student to apply different integration techniques including polynomial integration, integration by parts, and trigonometric integral methods.
1. **Polynomial Integration**:
- The first integral, \(\int (2 - x^2)^4 \; dx\), requires binomial expansion or a substitution method to simplify before integrating.
2. **Integration Using Substitution**:
- The second integral, \(\int \frac{x \; dx}{9 + x^2}\), may benefit from a simple substitution to simplify the ratio into a more straightforward integral.
3. **Partial Fraction Decomposition**:
- In the third integral, \(\int \frac{x^2 - 5x + 6 \; dx}{x^3 - 2x^2 + x}\), partial fraction decomposition can be utilized to break down the complex fraction before integrating term-by-term.
4. **Integration by Parts**:
- For the fourth integral, \(\int x e^{\frac{3}{5} x} \; dx\), integration by parts would be an effective method to solve it.
5. **Logarithmic Integration**:
- The fifth integral, \(\int x^3 \ln x \; dx\), is another case where integration by parts will be essential due to the presence of the logarithmic function.
6. **Trigonometric Integral**:
- The sixth integral, \(\int \cos
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