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2) Which reactant is oxidized in the following reaction: 12 + 2S203²- = 21 + S40g²-

2) Which reactant is oxidized in the following reaction: 12 + 2S203²- = 21 + S40g²-

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question 2: Which reactant is oxidized in the following reaction?** \[ \text{I}_2 + 2\text{S}_2\text{O}_3^{2-} \rightleftharpoons 2\text{I}^- + \text{S}_4\text{O}_6^{2-} \] **Explanation of Reaction:** In this chemical equation, iodine (\(\text{I}_2\)) and thiosulfate ions (\(\text{S}_2\text{O}_3^{2-}\)) are reactants, while iodide ions (\(\text{I}^-\)) and tetrathionate ions (\(\text{S}_4\text{O}_6^{2-}\)) are the products. **Oxidation Process:** Oxidation involves the loss of electrons. In this reaction: - Iodine (\(\text{I}_2\)) is converted to iodide ions (\(\text{I}^-\)), indicating a gain of electrons and thus, a reduction. - Thiosulfate ions (\(\text{S}_2\text{O}_3^{2-}\)) are transformed into tetrathionate ions (\(\text{S}_4\text{O}_6^{2-}\)). The focus is on the thiosulfate ions as they undergo oxidation, meaning they lose electrons during the reaction process.
Transcribed Image Text:**Question 2: Which reactant is oxidized in the following reaction?** \[ \text{I}_2 + 2\text{S}_2\text{O}_3^{2-} \rightleftharpoons 2\text{I}^- + \text{S}_4\text{O}_6^{2-} \] **Explanation of Reaction:** In this chemical equation, iodine (\(\text{I}_2\)) and thiosulfate ions (\(\text{S}_2\text{O}_3^{2-}\)) are reactants, while iodide ions (\(\text{I}^-\)) and tetrathionate ions (\(\text{S}_4\text{O}_6^{2-}\)) are the products. **Oxidation Process:** Oxidation involves the loss of electrons. In this reaction: - Iodine (\(\text{I}_2\)) is converted to iodide ions (\(\text{I}^-\)), indicating a gain of electrons and thus, a reduction. - Thiosulfate ions (\(\text{S}_2\text{O}_3^{2-}\)) are transformed into tetrathionate ions (\(\text{S}_4\text{O}_6^{2-}\)). The focus is on the thiosulfate ions as they undergo oxidation, meaning they lose electrons during the reaction process.
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