(2) suppose the open-loop amplifier (or simply the OpAmp) in the above feedbackamplifier has the following simulated magnitude and phase response. Some of the datapoints are given below:fs =175kHz, Mag(fg)= 42DB, Phase(f;) =-180degf, =120KHZ, Mag(f,)=48dB, Phase(f;) =-150degfo =100kHz, Mag(f.)=51DB,Phase(f.)=-135degfs = 85kHz, Mag(f,)=53dB, Phase(f;) =-115degf = 77kHz, Mag(f.)=55dB, Phase(f.)=-105degf3 = 45kHz, Mag((f,)=57&B, Phase(S,) =-75deg%3D%3D%3D%3D%3DPhase (deg)20 loglal(dB)7060-504240-100-15020-180-200-25020t-270IOM-10Ik10kIMJOM100kIM100kIk(a) Magnitude(b) Phase(without pole compensation), from the plots or the data given, calculate the requiredfeedback coefficient B for a phase margin of 75 degrees.(3) (without pole compensation) with the above magnitude and phase plots, suppose weenforce B = 0.0025 as the feedback coefficient, find the resulting gain margin of thefeedback amplifier.

The magnitude response is the ratio of the frequency amplitude of the output signal to the frequency…

(2) suppose the open-loop amplifier (or simply the OpAmp) in the above feedback amplifier has the following simulated magnitude and phase response. Some of the data points are given below: f=175kHz, Mag(f) 42 B, Phase(f.) -180deg f, =120kHz, Mag(f,)= 48dB, Phase(f,) =-150deg fo =100kHz, Mag(f.)=51DB, Phase(f)=-135deg f, = 85kHz, Mag(f,) = 53dB, Phase(f,) =-115deg f.=77kHz, Mag(f.)%=55dB, Phase(f.)=-105deg f=45kHz, Mag(S5)=57&B,Phase(S,) =-75deg %3D %3D %3D %3D %3D %3D %3D %3D Phase (deg) 20 loglalcan) 70 60 -50 -100 40 -150 20 -180 -200 -250 -10 2000-270 IOM Ik 10k 100k IM 1OM IM (b) hase (a) Magnitude (without pole compensation), from the plots or the data given, calculate the required feedback coefficient B for a phase margin of 75 degrees (3) (without pole compensation) with the above magnitude and phase plots, suppose we enforce B = 0.0025 as the feedback coefficient, find the resulting gain margin of the feedback amplifier. %3!

(2) suppose the open-loop amplifier (or simply the OpAmp) in the above feedback amplifier has the following simulated magnitude and phase response. Some of the data points are given below: f=175kHz, Mag(f) 42 B, Phase(f.) -180deg f, =120kHz, Mag(f,)= 48dB, Phase(f,) =-150deg fo =100kHz, Mag(f.)=51DB, Phase(f)=-135deg f, = 85kHz, Mag(f,) = 53dB, Phase(f,) =-115deg f.=77kHz, Mag(f.)%=55dB, Phase(f.)=-105deg f=45kHz, Mag(S5)=57&B,Phase(S,) =-75deg %3D %3D %3D %3D %3D %3D %3D %3D Phase (deg) 20 loglalcan) 70 60 -50 -100 40 -150 20 -180 -200 -250 -10 2000-270 IOM Ik 10k 100k IM 1OM IM (b) hase (a) Magnitude (without pole compensation), from the plots or the data given, calculate the required feedback coefficient B for a phase margin of 75 degrees (3) (without pole compensation) with the above magnitude and phase plots, suppose we enforce B = 0.0025 as the feedback coefficient, find the resulting gain margin of the feedback amplifier. %3!

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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