2) Starting with benzene, outline a synthesis for each of the following: Z=O 0.1 0=2 b 0=6=0 -OH

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### Problem 2: Benzene Derivative Synthesis

**Objective:** Starting with benzene, outline a synthesis for each of the following compounds:

- **Compound a:** 
  - Structure: A benzene ring with two nitro groups (NO₂) attached at the 1,3-positions (meta position).

- **Compound b:** 
  - Structure: A benzene ring bonded to a phenyl group, forming biphenyl.

- **Compound c:**
  - Structure: A benzene ring with three substituents—a chlorine atom (Cl) at position 1, a sulfonic acid group (SO₃H) at position 2, and a nitro group (NO₂) at position 4.

- **Compound d:**
  - Structure: A secondary alcohol where the hydroxyl group (OH) is attached to a benzene ring substituted with a phenyl group.

**Instructions:** Describe a feasible synthetic pathway starting from benzene for each derivative. 

### Explanations:

- **Meta-dinitrobenzene (Compound a):**
  1. Initiate with nitration of benzene using concentrated nitric acid (HNO₃) and sulfuric acid (H₂SO₄) to introduce one nitro group.
  2. Perform a second nitration step under controlled conditions to achieve meta substitution.

- **Biphenyl (Compound b):**
  1. Use a coupling reaction such as the Suzuki or Ullmann reaction to join two benzene rings.

- **2-Chloro-4-nitrobenzenesulfonic acid (Compound c):**
  1. Start with sulfonation of benzene using fuming sulfuric acid to introduce an SO₃H group.
  2. Chlorinate the resulting sulfonic acid with Cl₂ in the presence of a catalyst.
  3. Nitrate the compound in concentrated HNO₃.

- **(1-Phenylethyl)benzene (Compound d):**
  1. Begin by performing a Friedel-Crafts alkylation of benzene with ethyl chloride (or another suitable ethyl source) using AlCl₃.
  2. Follow with a subsequent reaction to introduce a phenyl group, forming the secondary alcohol structure. 

These transformations explore fundamental organic reactions such as electrophilic aromatic substitution, coupling, and Friedel-Crafts alkyl
Transcribed Image Text:### Problem 2: Benzene Derivative Synthesis **Objective:** Starting with benzene, outline a synthesis for each of the following compounds: - **Compound a:** - Structure: A benzene ring with two nitro groups (NO₂) attached at the 1,3-positions (meta position). - **Compound b:** - Structure: A benzene ring bonded to a phenyl group, forming biphenyl. - **Compound c:** - Structure: A benzene ring with three substituents—a chlorine atom (Cl) at position 1, a sulfonic acid group (SO₃H) at position 2, and a nitro group (NO₂) at position 4. - **Compound d:** - Structure: A secondary alcohol where the hydroxyl group (OH) is attached to a benzene ring substituted with a phenyl group. **Instructions:** Describe a feasible synthetic pathway starting from benzene for each derivative. ### Explanations: - **Meta-dinitrobenzene (Compound a):** 1. Initiate with nitration of benzene using concentrated nitric acid (HNO₃) and sulfuric acid (H₂SO₄) to introduce one nitro group. 2. Perform a second nitration step under controlled conditions to achieve meta substitution. - **Biphenyl (Compound b):** 1. Use a coupling reaction such as the Suzuki or Ullmann reaction to join two benzene rings. - **2-Chloro-4-nitrobenzenesulfonic acid (Compound c):** 1. Start with sulfonation of benzene using fuming sulfuric acid to introduce an SO₃H group. 2. Chlorinate the resulting sulfonic acid with Cl₂ in the presence of a catalyst. 3. Nitrate the compound in concentrated HNO₃. - **(1-Phenylethyl)benzene (Compound d):** 1. Begin by performing a Friedel-Crafts alkylation of benzene with ethyl chloride (or another suitable ethyl source) using AlCl₃. 2. Follow with a subsequent reaction to introduce a phenyl group, forming the secondary alcohol structure. These transformations explore fundamental organic reactions such as electrophilic aromatic substitution, coupling, and Friedel-Crafts alkyl
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