2) Scale reading in accelerating elevator: The 10.0 kg mass is on a scale, and the 8.00 kg mass hangs from the other end of the string over the pulley as illustrated and the system is in an elevator on earth. (Pulley & string massless, frictionless.) (See PSL 5.2,5) a) If zero acceleration: what is the scale reading in Newtons? Explain. b) Now the elevator and the entire mass and pulley system accelerate together. The reading on the scale is now 9.80 N. Based on this, what do you think is the direction of acceleration? (Gut feeling.) c) Draw FBDs for both the 10 kg and the 8 kg masses (for the accelerating system). d) Use N2L to determine the (i) string tension and (ii) acceleration of the system. Does the direction of the acceleration agree with your answer earlier? Elevator 10 kg scale Since everything accelerates together in the same direction, make this your positive direction for all objects. 8 kg
2) Scale reading in accelerating elevator: The 10.0 kg mass is on a scale, and the 8.00 kg mass hangs from the other end of the string over the pulley as illustrated and the system is in an elevator on earth. (Pulley & string massless, frictionless.) (See PSL 5.2,5) a) If zero acceleration: what is the scale reading in Newtons? Explain. b) Now the elevator and the entire mass and pulley system accelerate together. The reading on the scale is now 9.80 N. Based on this, what do you think is the direction of acceleration? (Gut feeling.) c) Draw FBDs for both the 10 kg and the 8 kg masses (for the accelerating system). d) Use N2L to determine the (i) string tension and (ii) acceleration of the system. Does the direction of the acceleration agree with your answer earlier? Elevator 10 kg scale Since everything accelerates together in the same direction, make this your positive direction for all objects. 8 kg
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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a) The scale will read 19.6 N.
Explanation:
Since the pulley and string is massless, the tension on both sides will be same. For the 8 kg mass, since the acceleration of the system is zero, the tension on the string will be equal to it's weight
So, T = 8×g = 8g
For the 10 kg mass, the net downward force will be 10g - 8g = 2g.
This 2g will be the reading of the scale i.e 2×9.8 = 19.6 N
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