2) Scale reading in accelerating elevator: The 10.0 kg mass is on a scale, and the 8.00 kg mass hangs from the other end of the string over the pulley as illustrated and the system is in an elevator on earth. (Pulley & string massless, frictionless.) (See PSL 5.2,5) a) If zero acceleration: what is the scale reading in Newtons? Explain. b) Now the elevator and the entire mass and pulley system accelerate together. The reading on the scale is now 9.80 N. Based on this, what do you think is the direction of acceleration? (Gut feeling.) c) Draw FBDs for both the 10 kg and the 8 kg masses (for the accelerating system). d) Use N2L to determine the (i) string tension and (ii) acceleration of the system. Does the direction of the acceleration agree with your answer earlier? Elevator 10 kg scale Since everything accelerates together in the same direction, make this your positive direction for all objects. 8 kg

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question
**Scale Reading in Accelerating Elevator:**

The 10.0 kg mass is on a scale, and the 8.00 kg mass hangs from the other end of the string over the pulley as illustrated, and the system is in an elevator on Earth. (Pulley & string massless, frictionless.) (See PSL 5.2,5)

**a) If zero acceleration: what is the scale reading in Newtons? Explain.**

**b) Now the elevator and the entire mass and pulley system accelerate together. The reading on the scale is now 9.80 N. Based on this, what do you think is the direction of acceleration? (Gut feeling.)**

*Note:* Since everything accelerates together in the same direction, make this your positive direction for all objects.

**c) Draw FBDs for both the 10 kg and the 8 kg masses (for the accelerating system).**

**d) Use N2L to determine the (i) string tension and (ii) acceleration of the system. Does the direction of the acceleration agree with your answer earlier?**

**Diagram Explanation:**

The diagram depicts an elevator with a pulley system. The pulley supports a string, with a 10 kg mass on a scale at one end, and an 8 kg mass hanging at the other end. The elevator is shown as a rectangular box containing these elements.

- The 10 kg mass is directly on the scale.
- The 8 kg mass hangs freely, creating tension in the string as it passes over the pulley.

This setup is used to analyze forces and acceleration within the system as the elevator moves.
Transcribed Image Text:**Scale Reading in Accelerating Elevator:** The 10.0 kg mass is on a scale, and the 8.00 kg mass hangs from the other end of the string over the pulley as illustrated, and the system is in an elevator on Earth. (Pulley & string massless, frictionless.) (See PSL 5.2,5) **a) If zero acceleration: what is the scale reading in Newtons? Explain.** **b) Now the elevator and the entire mass and pulley system accelerate together. The reading on the scale is now 9.80 N. Based on this, what do you think is the direction of acceleration? (Gut feeling.)** *Note:* Since everything accelerates together in the same direction, make this your positive direction for all objects. **c) Draw FBDs for both the 10 kg and the 8 kg masses (for the accelerating system).** **d) Use N2L to determine the (i) string tension and (ii) acceleration of the system. Does the direction of the acceleration agree with your answer earlier?** **Diagram Explanation:** The diagram depicts an elevator with a pulley system. The pulley supports a string, with a 10 kg mass on a scale at one end, and an 8 kg mass hanging at the other end. The elevator is shown as a rectangular box containing these elements. - The 10 kg mass is directly on the scale. - The 8 kg mass hangs freely, creating tension in the string as it passes over the pulley. This setup is used to analyze forces and acceleration within the system as the elevator moves.
Expert Solution
Step 1

 

a) The scale will read 19.6 N.

Explanation:

Since the pulley and string is massless, the tension on both sides will be same. For the 8 kg mass, since the acceleration of the system is zero, the tension on the string will be equal to it's weight

So, T = 8×g = 8g

For the 10 kg mass, the net downward force will be 10g - 8g = 2g. 

This 2g will be the reading of the scale i.e 2×9.8 = 19.6 N

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
First law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON