stinguish between the use of G and g. s, Isaac Newton proposed a rule to quantify the known as gravity between objects that have mass. shown in the figure. (Figure 1) Newton's law of cation describes the magnitude of the attractive ce F between two objects with masses my and Fx = G(mm²). distance between the centers of the two objects and ational constant. al force is attractive, so in the figure it pulls to the ward m₂) and toward the left on m2 (toward m₁). al force acting on my is equal in magnitude to, but e in direction from, the gravitational force acting on d by Newton's third law. The magnitude of both ated with the equation given above. al constant G has the value G = 6.67 x 10-¹¹ N-m²/kg² 1 of 2 > Consider the earth following its nearly circular orbit (dashed curve) about the sun. (Eigure 2) The earth has mass me msun = 1.99 x 1030 kg. They are separated, center to center, by r = 93 million miles = 150 million km. Part A What is the magnitude of the gravitational force acting on the earth due to the sun? Express your answer in newtons. ▸ View Available Hint(s) 15. ΑΣΦΑ X X √x x x 3.531028

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Chapter1: Units, Trigonometry. And Vectors
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<Chapter 12 Homework
Item 7
situations;
to distinguish between the use of G and g.
In the late 1600s, Isaac Newton proposed a rule to quantify the
attractive force known as gravity between objects that have mass,
such as those shown in the figure. (Figure 1) Newton's law of
universal gravitation describes the magnitude of the attractive
gravitational force F between two objects with masses m₁ and
g
m₂ as
Fg
Figure
=
m1
G · (²
where r is the distance between the centers of the two objects and
G is the gravitational constant.
m1m2
p2
The gravitational force is attractive, so in the figure it pulls to the
right on m₁ (toward m2) and toward the left on m2 (toward m₁).
The gravitational force acting on m₁ is equal in magnitude to, but
exactly opposite in direction from, the gravitational force acting on
m2, as required by Newton's third law. The magnitude of both
forces is calculated with the equation given above.
The gravitational constant G has the value
G = 6.67 × 10-¹¹ N. m²/kg²
<
m₂
1 of 2
>
Part A
Consider the earth following its nearly circular orbit (dashed curve) about the sun. (Figure 2) The earth has mass mearth = 5.98 × 1024 kg and the sun has mass
msun = 1.99 × 1030 kg. They are separated, center to center, by r = 93 million miles = 150 million km.
What is the magnitude of the gravitational force acting on the earth due to the sun?
Express your answer in newtons.
► View Available Hint(s)
VO
xa
ΑΣΦ
Submit
Xb
a
3.53 1028
√x x x
Previous Answers
Part B Complete previous part(s)
<४
Part C Complete previous part(s)
|X|
X.10n
?
x ****
<
N
7 of 10
X Incorrect; Try Again; One attempt remaining
This answer is off by a power of 10. Did you do your calculation using kilometers instead of meters? You may need to review Conversion Between km and
m.
Review
Transcribed Image Text:<Chapter 12 Homework Item 7 situations; to distinguish between the use of G and g. In the late 1600s, Isaac Newton proposed a rule to quantify the attractive force known as gravity between objects that have mass, such as those shown in the figure. (Figure 1) Newton's law of universal gravitation describes the magnitude of the attractive gravitational force F between two objects with masses m₁ and g m₂ as Fg Figure = m1 G · (² where r is the distance between the centers of the two objects and G is the gravitational constant. m1m2 p2 The gravitational force is attractive, so in the figure it pulls to the right on m₁ (toward m2) and toward the left on m2 (toward m₁). The gravitational force acting on m₁ is equal in magnitude to, but exactly opposite in direction from, the gravitational force acting on m2, as required by Newton's third law. The magnitude of both forces is calculated with the equation given above. The gravitational constant G has the value G = 6.67 × 10-¹¹ N. m²/kg² < m₂ 1 of 2 > Part A Consider the earth following its nearly circular orbit (dashed curve) about the sun. (Figure 2) The earth has mass mearth = 5.98 × 1024 kg and the sun has mass msun = 1.99 × 1030 kg. They are separated, center to center, by r = 93 million miles = 150 million km. What is the magnitude of the gravitational force acting on the earth due to the sun? Express your answer in newtons. ► View Available Hint(s) VO xa ΑΣΦ Submit Xb a 3.53 1028 √x x x Previous Answers Part B Complete previous part(s) <४ Part C Complete previous part(s) |X| X.10n ? x **** < N 7 of 10 X Incorrect; Try Again; One attempt remaining This answer is off by a power of 10. Did you do your calculation using kilometers instead of meters? You may need to review Conversion Between km and m. Review
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