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2) One night while on a vacation in the Caribbean, you walk to the end of a dock and for no particular reason, shine your laser pointer into the water. When you shine the beam of light on the water a horizontal distance of 2.4 meters from the dock, you see a glint of light from a shiny object on the sandy bottom – perhaps a gold coin. If the pointer is 1.8meters above the surface of the water, and the water is 5.5 meter deep, what is the horizontal distance (x) from the end of the dock to the shiny object? = 1.00 1.8 m 12 = 1.33 5.5 m - 24 m-- Hint: We can use Snell's law and basic trigonometry to find the horizontal distance to the shiny object. First, the information given in the problem determines the angle of incidence 01. In particular, we can see from the sketch that Length of the opposite leg Length of the adajecent leg tan 8, Second, Snell's law can be used to find angle of refraction, 02 Finally, the sketch shows that the horizontal distance to the shiny object is 2.4 m +x We can find the distance x from, Length of the opposite leg Length of the adajecent leg tan 02 =

2) One night while on a vacation in the Caribbean, you walk to the end of a dock and for no particular reason, shine your laser pointer into the water. When you shine the beam of light on the water a horizontal distance of 2.4 meters from the dock, you see a glint of light from a shiny object on the sandy bottom – perhaps a gold coin. If the pointer is 1.8meters above the surface of the water, and the water is 5.5 meter deep, what is the horizontal distance (x) from the end of the dock to the shiny object? = 1.00 1.8 m 12 = 1.33 5.5 m - 24 m-- Hint: We can use Snell's law and basic trigonometry to find the horizontal distance to the shiny object. First, the information given in the problem determines the angle of incidence 01. In particular, we can see from the sketch that Length of the opposite leg Length of the adajecent leg tan 8, Second, Snell's law can be used to find angle of refraction, 02 Finally, the sketch shows that the horizontal distance to the shiny object is 2.4 m +x We can find the distance x from, Length of the opposite leg Length of the adajecent leg tan 02 =

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Problems on optics 2) One night while on a vacation in the Caribbean, you walk to the end of a dock and for no particular reason, shine your laser pointer into the water. When you shine the beam of light on the water a horizontal distance of 2.4 meters from the dock, you see a glint of light from a shiny object on the sandy bottom – perhaps a gold coin. If the pointer is 1.8meters above the surface of the water, and the water is 5.5 meter deep, what is the horizontal distance (x) from the end of the dock to the shiny object? 1.8 m =1.00 12 = 1.33 5.5 m -2.4 m Hint: We can use Snell's law and basic trigonometry to find the horizontal distance to the shiny object. First, the information given in the problem determines the angle of incidence 01. In particular, we can see from the sketch that Length of the opposite leg Length of the adajecent leg tan 6, Second, Snell's law can be used to find angle of refraction, 02 Finally, the sketch shows that the horizontal distance to the shiny object is 2.4 m + x We can find the distance x from, Length of the opposite leg Length of the adajecent leg tan 0, =
Transcribed Image Text:Problems on optics 2) One night while on a vacation in the Caribbean, you walk to the end of a dock and for no particular reason, shine your laser pointer into the water. When you shine the beam of light on the water a horizontal distance of 2.4 meters from the dock, you see a glint of light from a shiny object on the sandy bottom – perhaps a gold coin. If the pointer is 1.8meters above the surface of the water, and the water is 5.5 meter deep, what is the horizontal distance (x) from the end of the dock to the shiny object? 1.8 m =1.00 12 = 1.33 5.5 m -2.4 m Hint: We can use Snell's law and basic trigonometry to find the horizontal distance to the shiny object. First, the information given in the problem determines the angle of incidence 01. In particular, we can see from the sketch that Length of the opposite leg Length of the adajecent leg tan 6, Second, Snell's law can be used to find angle of refraction, 02 Finally, the sketch shows that the horizontal distance to the shiny object is 2.4 m + x We can find the distance x from, Length of the opposite leg Length of the adajecent leg tan 0, =
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