2] Now, let's consider what happens when things get away from ideal a bit. Let's repeat the divider analysis, butthis time assume that the voltmeter pulls an appreciable current. Imagine that the divider resistors above are quitelarge in value, say R = 1 MM, and comparable to the voltmeter's internal resistance of Rvolt = 10 Mn. In a caselike this, we have to model the voltmeter as a simple resistor, and then analyze the circuit on the right.Vs112VtiltR1 31ΜΩR21ΜΩXMM1Vs12VtillRx 1MQwwwRy*1ΜΩRvolt10ΜΩA) Notice that R., and Rvolt are in parallel. Determine their parallel equivalent resistance Rp.B) Redraw the circuit with Rp in the place of Ry and Rvolt. Analyze the resulting simple voltage dividercircuit, and determine the measured voltage Vmeas across Ry.C) Ideally, the measured voltage would be Videal = 6 Volts if the voltmeter was perfect. What is the percenterror in this case?

2] Now, let's consider what happens when things get away from ideal a bit. Let's repeat the divider analysis, but this time assume that the voltmeter pulls an appreciable current. Imagine that the divider resistors above are quite large in value, say R = 1 M, and comparable to the voltmeter's internal resistance of Rvolt = 10 Mn. In a case like this, we have to model the voltmeter as a simple resistor, and then analyze the circuit on the right. Vs1 12V till R11MQ R2 1MQ XMM1 [017] Vs 12V tilt Rx1MQ www Ry 1MQ Rvolt 10ΜΩ A) Notice that Ry, and Rvolt are in parallel. Determine their parallel equivalent resistance Rp. B) Redraw the circuit with R₂ in the place of Ry and Rvolt. Analyze the resulting simple volta circuit, and determine the measured voltage Vmeas across Ry. C) Ideally, the measured voltage would be Videal = 6 Volts if the voltmeter was perfect. What is the percent error in this case?

2] Now, let's consider what happens when things get away from ideal a bit. Let's repeat the divider analysis, but this time assume that the voltmeter pulls an appreciable current. Imagine that the divider resistors above are quite large in value, say R = 1 M, and comparable to the voltmeter's internal resistance of Rvolt = 10 Mn. In a case like this, we have to model the voltmeter as a simple resistor, and then analyze the circuit on the right. Vs1 12V till R11MQ R2 1MQ XMM1 [017] Vs 12V tilt Rx1MQ www Ry 1MQ Rvolt 10ΜΩ A) Notice that Ry, and Rvolt are in parallel. Determine their parallel equivalent resistance Rp. B) Redraw the circuit with R₂ in the place of Ry and Rvolt. Analyze the resulting simple volta circuit, and determine the measured voltage Vmeas across Ry. C) Ideally, the measured voltage would be Videal = 6 Volts if the voltmeter was perfect. What is the percent error in this case?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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