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2 Name: Maile Velazquez Date: Period: 6 H-02 Equilibrium Assignment Instructions: Write the Law of Mass Action for each of the following chemical equations and then calculate the indicated missing variable using the provided information while at equilibrium. Ex H2O + COH₂+ CO₂ 1H2O+ 1CO1H2 + 1CO₂ [H2]¹[CO2]¹ K₂ = Кс 4.73 [H,O][CO] [CO2] = [H2]¹ (4.73)(0.0322)(0.0510) [H2O] 0.0322 M [CO₂] = = 0.0135088 (0.575) [CO] 0.0510 M [H2]¹[CO2] [CO2] = 0.0135 M [H2] 0.575 M [H,O][CO] H₂+2 << HI 43.8 0.0531 M K [HI] = 0.0785 M [H2] [12] -> A₁₂+ B₂ → AB3 [AB3] 0.146 M [A₂] 1.50 M K = K₁ = [B2] 0.240 M

2 Name: Maile Velazquez Date: Period: 6 H-02 Equilibrium Assignment Instructions: Write the Law of Mass Action for each of the following chemical equations and then calculate the indicated missing variable using the provided information while at equilibrium. Ex H2O + COH₂+ CO₂ 1H2O+ 1CO1H2 + 1CO₂ [H2]¹[CO2]¹ K₂ = Кс 4.73 [H,O][CO] [CO2] = [H2]¹ (4.73)(0.0322)(0.0510) [H2O] 0.0322 M [CO₂] = = 0.0135088 (0.575) [CO] 0.0510 M [H2]¹[CO2] [CO2] = 0.0135 M [H2] 0.575 M [H,O][CO] H₂+2 << HI 43.8 0.0531 M K [HI] = 0.0785 M [H2] [12] -> A₁₂+ B₂ → AB3 [AB3] 0.146 M [A₂] 1.50 M K = K₁ = [B2] 0.240 M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2 Name: Maile Velazquez Date: Period: 6 H-02 Equilibrium Assignment Instructions: Write the Law of Mass Action for each of the following chemical equations and then calculate the indicated missing variable using the provided information while at equilibrium. Ex H2O + COH₂+ CO₂ 1H2O+ 1CO1H2 + 1CO₂ [H2]¹[CO2]¹ K₂ = Кс 4.73 [H,O][CO] [CO2] = [H2]¹ (4.73)(0.0322)(0.0510) [H2O] 0.0322 M [CO₂] = = 0.0135088 (0.575) [CO] 0.0510 M [H2]¹[CO2] [CO2] = 0.0135 M [H2] 0.575 M [H,O][CO] H₂+2 << HI 43.8 0.0531 M K [HI] = 0.0785 M [H2] [12] -> A₁₂+ B₂ → AB3 [AB3] 0.146 M [A₂] 1.50 M K = K₁ = [B2] 0.240 M
Transcribed Image Text:2 Name: Maile Velazquez Date: Period: 6 H-02 Equilibrium Assignment Instructions: Write the Law of Mass Action for each of the following chemical equations and then calculate the indicated missing variable using the provided information while at equilibrium. Ex H2O + COH₂+ CO₂ 1H2O+ 1CO1H2 + 1CO₂ [H2]¹[CO2]¹ K₂ = Кс 4.73 [H,O][CO] [CO2] = [H2]¹ (4.73)(0.0322)(0.0510) [H2O] 0.0322 M [CO₂] = = 0.0135088 (0.575) [CO] 0.0510 M [H2]¹[CO2] [CO2] = 0.0135 M [H2] 0.575 M [H,O][CO] H₂+2 << HI 43.8 0.0531 M K [HI] = 0.0785 M [H2] [12] -> A₁₂+ B₂ → AB3 [AB3] 0.146 M [A₂] 1.50 M K = K₁ = [B2] 0.240 M
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