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2 Lazy primality testing (. Checking whether a number is prime is difficult. You decide to check the following condition instead: P(n): the last digit of n is one of 1,3,7,9. You are using this test to check two-digit numbers only: integers that are at least 10 and less than 100. Assuming n € Z and 10 ≤ n < 100, is P(n) a necessary condition for n to be prime? Assuming n € Z and 10 ≤ n < 100, is P(n) a sufficient condition for n to be prime?

2 Lazy primality testing (. Checking whether a number is prime is difficult. You decide to check the following condition instead: P(n): the last digit of n is one of 1,3,7,9. You are using this test to check two-digit numbers only: integers that are at least 10 and less than 100. Assuming n € Z and 10 ≤ n < 100, is P(n) a necessary condition for n to be prime? Assuming n € Z and 10 ≤ n < 100, is P(n) a sufficient condition for n to be prime?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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2 Lazy primality testing ( Checking whether a number is prime is difficult. You decide to check the following condition instead: P(n): the last digit of n is one of 1,3,7,9. You are using this test to check two-digit numbers only: integers that are at least 10 and less than 100. Assuming n € Z and 10 ≤ n < 100, is P(n) a necessary condition for n to be prime? Assuming n € Z and 10 ≤ n < 100, is P(n) a sufficient condition for n to be prime?
Transcribed Image Text:2 Lazy primality testing ( Checking whether a number is prime is difficult. You decide to check the following condition instead: P(n): the last digit of n is one of 1,3,7,9. You are using this test to check two-digit numbers only: integers that are at least 10 and less than 100. Assuming n € Z and 10 ≤ n < 100, is P(n) a necessary condition for n to be prime? Assuming n € Z and 10 ≤ n < 100, is P(n) a sufficient condition for n to be prime?
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