13. 2 kg of air at 5 bar, 80°C expands adiabatically in a closed system until its volume is doubled and itstemperature becomes equal to that of the surroundings which is at 1 bar, 5°C. For this process, determine :(i) The maximum work;(i) The change in availability;(iii) The irreversibility.For air take :c, = 0.718 kJ/kg K, u = c T, where c, is constant and pV = mRT, where p is in bar, v volumein m', m mass in kg, R is constant equal to 0.287 kJ/kg K, and T temperature in K.[Ans. (i) 122.72 kJ ; (ii) 82.2 kJ ; (iii) 15.2 kJ]

Given Data m=2 kgP1=500 kPaT1=80oCP2=100 kPaT2=5oC=278 KCv=0.718KJKg·KR=0.287 KJKg·K (a) maximum…

2 kg of air at 5 bar, 80°C expands adiabatically in a closed system until its volume is doubled and its temperature becomes equal to that of the surroundings which is at 1 bar, 5°C. For this process, determine : (i) The maximum work ; (ii) The change in availability; (iii) The irreversibility. For air take :e = 0.718 kJ/kg K, u = c, T, where c, is constant and pV = mRT, where p is in bar, V volume in m', m mass in kg, R is constant equal to 0.287 kJ/kg K, and T temperature in K. [Ans. (i) 122.72 kJ ; (i) 82.2 kJ ; (i) 15.2 kJ]

2 kg of air at 5 bar, 80°C expands adiabatically in a closed system until its volume is doubled and its temperature becomes equal to that of the surroundings which is at 1 bar, 5°C. For this process, determine : (i) The maximum work ; (ii) The change in availability; (iii) The irreversibility. For air take :e = 0.718 kJ/kg K, u = c, T, where c, is constant and pV = mRT, where p is in bar, V volume in m', m mass in kg, R is constant equal to 0.287 kJ/kg K, and T temperature in K. [Ans. (i) 122.72 kJ ; (i) 82.2 kJ ; (i) 15.2 kJ]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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